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Ivenika [448]
3 years ago
6

Can someone please help me with this ??

Mathematics
1 answer:
Elis [28]3 years ago
7 0

Answer:

future: a day, a week, or even a few months from now.

short-term goal

long-term goal

intermediate goal

specific goa

Step-by-step explanation:

please mark me as brainliest hi

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7-4 pls help pleasssssssssssssssse
dolphi86 [110]

Answer:

for what subject?

geometry

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algebra

5 0
3 years ago
Read 2 more answers
A grain silo has a circular base with an area of 260 square feet and is 21 feet tall What is the total volume?​
Leya [2.2K]

The correct answer is 5460 cubic feet or 5460 ft^{3}

Explanation:

The silo has a cylindrical shape, in this context, the volume of the silo or any other cylinder can be calculated by using the formula Volume =\pi r^{2} h. In this formula the symbol \pi refers to the number 3.1415..., the letter r refers to the radius of the base and the letter h refers to the height.

Moreover, in this case, it is known the heigh (21 feet) and the area of the base (260 square feet). Additionally, this area of the base is the result of the formula Area = \pi r^{2}, which is exactly the first section of the formula to find the volume. This implies that by multiplying the area of the base by the height the volume is known. Here is the process:

Volume = \pi r^{2} h  or  Volume = Ah   (Area of the base × height)

V = 260 square feet × 21 feet

V = 5460 cubic feet

6 0
3 years ago
Lagrange multipliers have a definite meaning in load balancing for electric network problems. Consider the generators that can o
Ivahew [28]

Answer:

The load balance (x_1,x_2,x_3)=(545.5,272.7,181.8) Mw minimizes the total cost

Step-by-step explanation:

<u>Optimizing With Lagrange Multipliers</u>

When a multivariable function f is to be maximized or minimized, the Lagrange multipliers method is a pretty common and easy tool to apply when the restrictions are in the form of equalities.

Consider three generators that can output xi megawatts, with i ranging from 1 to 3. The set of unknown variables is x1, x2, x3.

The cost of each generator is given by the formula

\displaystyle C_i=3x_i+\frac{i}{40}x_i^2

It means the cost for each generator is expanded as

\displaystyle C_1=3x_1+\frac{1}{40}x_1^2

\displaystyle C_2=3x_2+\frac{2}{40}x_2^2

\displaystyle C_3=3x_3+\frac{3}{40}x_3^2

The total cost of production is

\displaystyle C(x_1,x_2,x_3)=3x_1+\frac{1}{40}x_1^2+3x_2+\frac{2}{40}x_2^2+3x_3+\frac{3}{40}x_3^2

Simplifying and rearranging, we have the objective function to minimize:

\displaystyle C(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)

The restriction can be modeled as a function g(x)=0:

g: x_1+x_2+x_3=1000

Or

g(x_1,x_2,x_3)= x_1+x_2+x_3-1000

We now construct the auxiliary function

f(x_1,x_2,x_3)=C(x_1,x_2,x_3)-\lambda g(x_1,x_2,x_3)

\displaystyle f(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)-\lambda (x_1+x_2+x_3-1000)

We find all the partial derivatives of f and equate them to 0

\displaystyle f_{x1}=3+\frac{2}{40}x_1-\lambda=0

\displaystyle f_{x2}=3+\frac{4}{40}x_2-\lambda=0

\displaystyle f_{x3}=3+\frac{6}{40}x_3-\lambda=0

f_\lambda=x_1+x_2+x_3-1000=0

Solving for \lambda in the three first equations, we have

\displaystyle \lambda=3+\frac{2}{40}x_1

\displaystyle \lambda=3+\frac{4}{40}x_2

\displaystyle \lambda=3+\frac{6}{40}x_3

Equating them, we find:

x_1=3x_3

\displaystyle x_2=\frac{3}{2}x_3

Replacing into the restriction (or the fourth derivative)

x_1+x_2+x_3-1000=0

\displaystyle 3x_3+\frac{3}{2}x_3+x_3-1000=0

\displaystyle \frac{11}{2}x_3=1000

x_3=181.8\ MW

And also

x_1=545.5\ MW

x_2=272.7\ MW

The load balance (x_1,x_2,x_3)=(545.5,272.7,181.8) Mw minimizes the total cost

5 0
3 years ago
Solve the equation<br> A+b - c =180 for C
spayn [35]
A = 180
b = 180
c = 180

180+180-180 = 180
5 0
3 years ago
A man climbing a banana tree. Which sentence achieves the purpose of telling the man that what he is doing is dangerous? How do
hichkok12 [17]

Answer:

Be careful!

Step-by-step explanation:

7 0
3 years ago
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