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alina1380 [7]
1 year ago
8

Question 1 of 20:

Physics
1 answer:
xxMikexx [17]1 year ago
4 0

Unlike the IQ, your emotional intelligence (EQ) <u>may be improved over time by becoming more mindful</u>

<u />

Emotional intelligence is the understanding and usage of one's own emotions in a positive way to relieve their stress. It also helps for effective communication, to overcome challenges, to empathize and to defuse any bad situation.

Option A is the correct for IQ ( Intelligence quotient ). Option C is wrong because EQ can be built in any stage of your life. EQ is basically emotions. So option D is incorrect.

Therefore, Unlike the IQ, your emotional intelligence (EQ) may be improved over time by becoming more mindful

<u />

To know more about emotional intelligence

brainly.com/question/13129837

#SPJ1

You might be interested in
In this circuit the resistance R1 is 7 Ω and R2 is 3 Ω. If this combination of resistors were to be replaced by a single resisto
Scilla [17]

Answer:

Series combination:

Equivalent resistance =10Ω

Parallel combination:

Equivalent resistance =\frac{21}{10} \Omega

Explanation:

Resistance: Resistance is the ratio of voltage to the current.

R=\frac{V}{I}

R = resistance

I = current

V= potential difference(voltage)

There are two types of resistance combinations.

  1. series combination
  2. parallel combination.

Series combination: If the ending point of one resistance is connected to the starting point of other resistance that combination is known as series combination.

If R₁,R₂ and R₃  are connected in series combination.

Then equivalent resistance = R₁+R₂+R₃

Parallel combination: If the ending point and the starting point of the all resistance are the same points that combination is known as parallel combination.

If R₁,R₂ and R₃  are connected in parallel combination.

Then equivalent resistance  \frac{1}{R}= \frac{1}{R_1}+ \frac{1}{R_2}+\frac{1}{R_3}

Here R₁=7Ω and     R₂=3Ω

If R₁ and R₂  connected in series combination

Then equivalent resistance = (7+3) Ω

                                            =10Ω

If R₁ and R₂  connected in parallel combination

Then equivalent resistance =\frac{1}{(\frac{1}{7} +\frac{1}{3})} \Omega

                                              =\frac{21}{10} \Omega

5 0
3 years ago
- What are (a) the x component, (b) the y component, and (c) the z component of r = a - b +c if a= 7.8 + 6.6 - 7.1 , b= -2.9 + 7
frez [133]

Answer:

Explanation:

a= 7.8i + 6.6j - 7.1k

b=   -2.9 i+ 7.4 j+ 3.9k , and

c = 7.6i + 8.8j + 2.2k

r = a - b +c

=7.8i + 6.6j - 7.1k - ( -2.9i + 7.4j+ 3.9k )+ ( 7.6i + 8.8j + 2.2k)

= 7.8i + 6.6j - 7.1k +2.9i - 7.4j- 3.9k )+  7.6i + 8.8j + 2.2k

= 18.3 i +18.3 j - k

the angle between r and the positive z axis.

cosθ = 18.3 / √18.3² +18.3² +1

the angle between r and the positive z axis.

= 18.3 / 25.75

cos θ= .71

45 degree

6 0
3 years ago
gAn optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is from the
igomit [66]

Answer:

d = 68.5 x 10⁻⁶ m = 68.5 μm

Explanation:

The complete question is as follows:

An optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is  1.70m from the slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be?

The answer can be given by using the formula derived from Young's Double Slit Experiment:

y = \frac{\lambda L}{d}\\\\d  =\frac{\lambda L}{y}\\\\

where,

d = slit separation = ?

λ = wavelength = 633 nm = 6.33 x 10⁻⁷ m

L = distance from screen (detector) = 1.7 m

y = distance between bright fringes = 15.7 mm = 0.0157 m

Therefore,

d = \frac{(6.33\ x\ 10^{-7}\ m)(1.7\ m)}{0.0157\ m}\\\\

<u>d = 68.5 x 10⁻⁶ m = 68.5 μm</u>

7 0
3 years ago
The volume of a piece of metal of a mass 6 gram is 15cm3. What is the density of the metal piece?
torisob [31]

Answer:

0.4 g/cm^3

Explanation:

The density of an object can be found using the following formula.

d= m/v

where m is the mass and v is the volume.

The mass of the metal is 6 grams and the volume is 15 centimeters^3

m=6 g

v= 15 cm^3

Substitute these into the formula.

d= 6 g/ 15 cm^3

Divide 6 g by 15 cm^3 (6/15=0.4)

d= 0.4 g/ cm^3

The density of the metal is 0.4 grams per cubic centimeter.

4 0
3 years ago
Read 2 more answers
Which object is an example of a mechical wave
stiks02 [169]

Answer:

Jump Rope.

Explanation:

7 0
2 years ago
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