Answer:
25m
Explanation:
Let's assume the Jeep attains a velocity of 36km/h ; a constant speed same with that of the car.
While the Jeep is accelerating to that speed, the car with that speed passes it.
Now we can calculate the time taken for the Jeep to attain the velocity of 36km/h on her constant acceleration.
This time is t = v/a; from Newton's Law of Motion:
a = V-U / t ; a-acceleration
V is final velocity = 36km/h
U is initial velocity 0 since the body starts from rest.
Hence t = 36000/3600 ÷ 4 = 2.5s
Note conversting from km/h to m/s we multiply by 1000/3600.
But the distance covered by the car while the Jeep just accelerates is
S = U × t = 10× 2.5 = 25m.
Note From Newton's law of Motion, distance for constant speed is defined as: U × t
Hence the Car would be 25m off the starting point just as the Jeep accelerates. It would overtake the Jeep when it just covers 25m from the Jeep starting point.
10 x 4^2 = 160 / 8..
V = 20m/s...
...x 8 = 100 miles,meters, metric what ever m stands for after 8 seconds.
This is my guess since the problem says 4m/s^2
V= distance/ ST (traveled/used)
Answer:
Frequency – The frequency of a wave is the number of waves that pass a given point in a certain amount of time. Frequency is measured in units called hertz (Hz), and is defined as the number of waves per second. A wave that occurs every second has a frequency of 1 wave per second (1/s) or 1 Hz.
Answer:
(D) Vf² = Vi² + 2ad
a = 2.269 m/s²
Explanation:
Given;
final velocity of the aircraft, Vf = 33 m/s
initial velocity of the aircraft, Vi = 0
distance traveled by the plane, d = 240 m
The acceleration of the plane is given by the following kinematic equation;
Vf² = Vi² + 2ad
where;
a is the acceleration;
Based on the given options, the correct option is "D".
Calculating the acceleration with the chosen equation;
Vf² = Vi² + 2ad
Vf² = 0+ 2ad
Vf² = 2ad
a = Vf² / 2d
a = (33)² / (2 x 240)
a = 2.269 m/s²