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JulijaS [17]
3 years ago
11

You are watching an object that is moving in shm. when the object is displaced 0.600 m to the right of its equilibrium position,

it has a velocity of 2.20 m>s to the right and an acceleration of 8.40 m>s 2 to the left. how much farther from this point will the object move before it stops momentarily and then starts to move back to the left?
Physics
1 answer:
larisa [96]3 years ago
8 0
It should take at least 4.50

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Which of the following chemical equations demonstrates that atoms are conserved during a chemical reaction?
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Explanation:

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A big wheel at a theme park has a diameter of 14m and people on the ride complete one revolution in 24s. calculate the distance
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Explanation:

We'll call the radius r and the diameter d:

We also assume that the riders are at a distance r = d/2 = 7m from the center of the wheel.

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2 years ago
Peg P is driven by the forked link OA along the path described by r = eu, where r is in meters. When u = p4 rad, the link has an
8_murik_8 [283]

Answer:

The transverse component of acceleration is 26.32 m/s^2 where as radial the component of acceleration is 8.77 m/s^2

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As per the given data

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r=e^u

So the transverse component of acceleration are given as

a_{\theta}=(ru''+2r'u')\\

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r=e^u\\r=e^{\pi/4}\\r=2.1932 m

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So

a_{\theta}=(ru''+2r'u')\\a_{\theta}=(2.1932\times 4+2\times 4.3864 \times 2)\\a_{\theta}=26.32 m/s\\

The transverse component of acceleration is 26.32 m/s^2

The radial component is given as

a_r=r''-r\theta'^2

Here

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a_r=r''-ru'^2\\a_r=17.5456-2.1932\times (2)^2\\a_r=8.7728 m/s^2

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3 years ago
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7 0
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eimsori [14]

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