Let
denote the rocket's position, velocity, and acceleration vectors at time
.
We're given its initial position

and velocity

Immediately after launch, the rocket is subject to gravity, so its acceleration is

where
.
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,


(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

and



b. The rocket stays in the air for as long as it takes until
, where
is the
-component of the position vector.

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

c. The rocket reaches its maximum height when its vertical velocity (the
-component) is 0, at which point we have


Answer: Answer: 14 : 12 , 21 : 18 and 28 : 24
Please brainliest i answer first
8.49 x 10⁻⁷ = 0.000000849
Answer:
yes
Step-by-step explanation:
(5_3)^2+2(0)=4
substitute with the 5 to x and 0 to y