I think it’s heat transfer but can’t guarantee
Answer:
a) 1,737 kJ
b) -1,93 kJ
Explanation:
The standard free energy change (ΔG) can be determined using:
ΔG = -nFE
a) For the reaction:
Fumarate²⁻ + CoQH₂ ⇄ succinate²⁻ + CoQ
The transferred electrons are 2, As E=-0,009V:
ΔG = -2×96,5kJ/molV×-0,009V
<em>ΔG = 1,737 kJ</em>
b) For the reaction:
cytc1 (Fe²⁺) + cytc (Fe³⁺) ⇄ cytc1 (Fe³⁺) + cytc (Fe²⁺)
The transferred electron is n=1 and E=0,02V:
ΔG = -1×96,5kJ/molV×0,02V
<em>ΔG = -1,93 kJ</em>
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I hope it helps!
Answer:
2 PO₄³⁻(aq) + 3 Fe²⁺(aq) ⇒ Fe₃(PO₄)₂
Explanation:
Let's consider the complete ionic equation between the ions present. It includes all the ions and the insoluble compounds (Fe₃(PO₄)₂ is insoluble).
Na⁺(aq) + 2 PO₄³⁻(aq) + 3 Fe²⁺(aq) + NO₃⁻(aq) ⇒ Fe₃(PO₄)₂ + Na⁺(aq) + NO₃⁻(aq)
The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the insoluble compounds.
2 PO₄³⁻(aq) + 3 Fe²⁺(aq) ⇒ Fe₃(PO₄)₂
Answer:
Possible lowest volume = 0.19 cm
Possible highest volume = 0.21 cm
Explanation:
given data
volumetric pipette uncertainty = 0.01 cm³
total volume = 0.20 cm³
solution
we will get here Possible lowest and highest volume that is express as
Possible lowest volume = total volume - uncertainty .....................1
Possible highest volume = total volume + uncertainty ....................2
put here value in both equation and we get
Possible lowest volume = 0.20 cm - 0.01 cm
Possible lowest volume = 0.19 cm
and
Possible highest volume = 0.20 cm + 0.01 cm
Possible highest volume = 0.21 cm
This means that the air in that city has less than a third of water vapor it could contain under the same circumstances. Relative humidity is the ratio of water vapor that the air contains to the maximum amount it could carry at the same temperature. When the humidity is high the water vapor in the air is a lot and vice versa.
