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3 years ago

If a gas occupies a volume of 950 mL at standard temperature, what volume will it

1 answer:

n200080 [17]3 years ago

3 0

Voulme 1= 950 mL
Volume 2= ?
Temperature 1 = 25 C
Temperature 2 = 50 C
Convert your temperature to Kelvin
C+273=K
Temperature 1 = 25 C + 273 = 298 K
Temperature 2 = 50 C + 273 = 323 K

Plug in to the Formula
950 mL/298 K = ? / 323 K

Rearrange the formula to make one to solve for what is missing.
To get 323 K out of the denominator multiply by it.
Making it
950 mL x 323 K / 298 K = ?

Plug it in
950 mL x 323 K / 298 K = 1027.9 mL

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If 2 molecules of one reactant combine with 3 molecules of another to produce 5 molecules of a product, then what is the represe

zhenek [66]

Answer:- $2A+3B\rightarrow 5C$

Explanations:- Let's say the first molecule is A and the second molecule is B and the product molecule is C.

From given information, 2 molecules of A react with 3 molecules of B to produce 5 molecules of C.

We write the reactants on left side and the product on right side and there is an arrow between them from reactants towards the products.

So, the reaction could be represented as:

$2A+3B\rightarrow 5C$

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3 years ago

An ionic bond is _?_

lubasha [3.4K]

It would be C, because Ionic bonds have to deal with valence electrons ( the outer shell ones)

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3 years ago

What is the mass in grams of 1.00 x 10 24 atoms of Mn?

Alex17521 [72]

<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 91.2321 \ g \ Mn$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

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Harlamova29_29 [7]

B the atomic number is 20 and then you subtract atomic mass to find the neutrons

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A sample of carbon-12 has a mass of 6.00 g. How many atoms of carbon-12 are in the sample?

Bingel [31]

Carbon molar mass=12
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3 years ago

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