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3 years ago

11

The blades of a metal cutter are shorter than the blades of paper cutter scissor. Give reason

1 answer:

Sladkaya [172]3 years ago

8 0

Answer:

Metal is a tougher material to cut though, so the blades must be shorter to create more pressure to break through the metal. Paper on the other hand is easier to cut through so the blades can be longer in order to cut more in each snip.

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The diagram below shows a subduction zone where oceanic crust is sinking into the mantle underneath continental crust as two

Scrat [10]

Metal ores

Explanation:

in an area where subduction has occurred in times past, metal ores are likely to be found.

Metallic ores find subduction zone regions very favorable to crystallize out of a magma.

Ores have different modes of formation.
Typically, they are found in hydrothermal vents and black smokers of igneous intrusives.
These are igneous terrains where metallic sulfides and other minerals crystallize out of magmatic body.
Metals in magma usually have large sizes and do not partition easily in the melt.

At a subduction zone, partial melting of the subducting plate forces magma into nearby country rock as an intrusive and to the ocean floor where they form black smokers.

Learn more:

Rocks brainly.com/question/2740663

#learnwithBrainly

4 0

3 years ago

A magnetic field is applied to a freely floating uniform iron sphere with radius R = 2.00 mm. The sphere initially had no net ma

grigory [225]

Answer:

$\omega=4.2704*10^-^5 rad/s$

Explanation:

Angular Momentum Formula For atoms= $L_{atom}=0.12Nm_{s}h$

Where:

m_{s}h is the momentum for one atom (m_s is the spin quantum number)

N is the number of atoms= $\frac{N_{A}*m}{M}$

Where:

N_A is Avogadro Number

m is the mass of sphere

M is the molar mass of iron

Angular Momentum Formula For atoms will be= $L_{atom}=0.12\frac{N_{A}m}{M} m_{s}h$

Angular Momentum of Sphere= $L_{sphere}=I\omega$

where:

$I=\frac{2mR^{2}}{5}$

So,Angular Momentum of Sphere= $L_{sphere}=\frac{2mR^{2}}{5}\omega$

Angular Momentum of sphere=Angular Momentum of atoms

$L_{sphere}$ = $L_{atom}$

$\frac{2mR^{2}}{5}\omega$ = $0.12\frac{N_{A}m}{M} m_{s}h$

For iron, $m_s =\frac{1}{2}$ . So above equation will become:

$\omega=\frac{0.12*5*N_{A}h}{4*M*R^{2} }$

Where R=2mm, M=0.0558Kg/mol (Molar Mass of iron),h=Planck's Constant/2π

$\omega=\frac{0.12*5*(6.022*10^{23})(6.63*10^{-34}/2*\pi)}{4*0.0558*(2*10^{-3})^{2}}$

$\omega=4.2704*10^-^5 rad/s$

5 0

3 years ago

Can you please help - the answer I got so far is 7.624 but when I enter it in my homework in Quest, it i stating that this answe

torisob [31]

Answer:

-7.04

Explanation:

9.8 multipled by -0.719 b

6 0

3 years ago

What does it mean if an object is electrically uncharged?

larisa86 [58]

The object has been golaced in water

5 0

2 years ago

A pendulum is transported from sea-level, where the acceleration due to gravity g is 9.80 m/s2, to the bottom of Death Valley. A

tatyana61 [14]

Answer: the value of g in Death Valley is 10.417 m/s²

Explanation:

Given that;

acceleration due to gravity at the point is g = 9.8 m/s²

Lets say the acceleration due to gravity at the bottom of Death valley is g'

as the period of the pendulum is decreased by 3.00%

T' = 0.97 T

T is the period of the pendulum at sea level and T' is the period of the pendulum at bottom of Death valley

therefore from the relation

T = 2π√(l/g)

g'/g = T²/T'²

g' = (T²/ (0.97T)²)g

g' = 1.063g

g' = 10.417 m/s²

therefore the value of g in Death Valley is 10.417 m/s²

7 0

3 years ago