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3 years ago

Asap!! help me giving brainliest! No guessing.

Mathematics

2 answers:

Nonamiya [84]3 years ago

4 0

Answer:

Step-by-step explanation:

560 miles

----------------------- = 11 bikers who ride 50 miles each, plus one more biker,

50 miles/biker who rides only 10 miles (from 550 to 560 miles)

kipiarov [429]3 years ago

4 0

Answer:

In a team bike race, a biker must ride exact 50 miles.

If they need to achieve 560 miles, the number of bikers should be a positive integer (b) which is equal or larger than: 560/50 = 11.2. => The answer should be b > 11 or b>=12.

Hope this helps!

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trapecia [35]

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2 years ago

Read 2 more answers

What should be the first step in solving 13 y − 14 = 42?

AveGali [126]

Answer:

The first step should be adding 14 to both sides of the equation.

Step-by-step explanation:

14 must be added on both sides of the equation to get 13y by itself. The ultimate goal is to get y by itself if we are solving for y.

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2 years ago

6. j + 1,239 = 1,300 (1 point) Oj=61 Oj=71 Oj = 59

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2 years ago

The smaller triangle is the image of the larger triangle after a dilation. The center of the dilation is (−3,−2). What is the sc

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2 years ago

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96m long and 74m wide.

Oduvanchick [21]

Answer:

$11402.66 m^{2}$

Step-by-step explanation:

The width of rectangle is the diameter of the semi-circle part

Area of one semicircle is given by $\frac {0.5\pi d^{2}}{4}$

Total area of semi circle will be $2\times\frac {0.5\pi d^{2}}{4}$

Substituting 74 m for d and $\pi$ as 3.14 we obtain

Total area semi-circle= $2\times\frac {0.5*3.14\times 74^{2}}{4}=4298.66 m^{2}$

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Rectangular area= $96 m*74 m=7104 m^{2}$

Total area of rectangular and semi-circles will be

$4298.66 m^{2}+7104 m^{2}=11402.66 m^{2}$

Therefore, area of training field is $11402.66 m^{2}$

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3 years ago