Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

For parts (a) and (b), you're given everything you need to determine

.
For part (c), if

and

are mutually exclusive, then

, so

. If the given probability is

, then you can find

. But if this given probability is for the intersection, finding

is impossible.
For part (d), if

and

are independent, then

.
Answer:
1. $60
2. 600 Calories were burned
3. D
Step-by-step explanation:
1. $75 x .20=$15
75-15=$60
2. What I started with is 200/40=5 calories burned per min
60 plus 60=120
5x120=600
3. It's the only option that has something decreasing. and there is a -5 which means it's getting subtracted or its decreasing.
Answer:
p = 35/4 = 8.750
Step-by-step explanation:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
4/7-(5/p)=0
Answer:
$1,080 please mark brainliest if satisfied
Step-by-step explanation:
1200 times 0.1 equals 120
1200 minus 120 equals 1080