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vaieri [72.5K]
3 years ago
13

Amelia has 3 gallons of paint .Mason have 10 quarts .How many more pints of paint does AMELIA have then mason.

Mathematics
1 answer:
Ber [7]3 years ago
6 0

Answer:

4 Pints

Step-by-step explanation:

According to the scenario, calculations are as follows,

As we know, 1 gallon = 8 Pints

1 Quarts = 2 Pints

So, Amelia = 3 Gallons = 3 × 8 Pints = 24 Pints

Mason = 10 quarts = 10 × 2 Pints = 20 Pints

So, Number of more pints Amelia has = Amelia number of pints - Mason number of pints

= 24 pints - 20 pints

= 4 Pints  

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A square plot of land has an area of 484m².What is the perimeter​
harina [27]

Answer:

Perimeter: 88m

Step-by-step explanation:

Area of the square plot = (Side) X (Side)

And we are given the area is 484m²,

therefore, (Side) X (Side) = 484m²

or,

(Side)² = 484, taking square root on both the sides,

\sqrt{(Side)^{2} } = \sqrt{484}

Side = 22m.

And we know that, perimeter of a square is = 4 X (Side)

Therefore, Perimeter = 4 X 22 = 88m

:-)

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In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th
MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

a)

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

\frac{20!}{18!2!}=190

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

b)

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

4 0
3 years ago
13, 5, 4, 9, 7, 14, 4 The deviations are _____.
fenix001 [56]

Answer:

B."5, -3, -4, 1, -1, 6, -4"

Step-by-step explanation:

We are given that

13,5,4,9,7,14,4

We have to find the deviation.

Mean=\frac{sum\;of\;data}{total\;number\;of\;data}

Using the formula

Mean,\mu=\frac{13+5+4+9+7+14+4}{7}

Mean,\mu=\frac{56}{7}=8

Deviation=x_i-\mu

         x_i-\mu

13          5

5           -3

4           - 4

9            1

7             -1

14            6

4            - 4

Hence, option  B is correct.

7 0
3 years ago
Y - 3 = -2(x -1)<br> How do i do this?
Masja [62]

Answer: -2

Step-by-step explanation:

y-intercept: (0,5)

5 0
3 years ago
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