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3 years ago

Answer all please!!!!!!!!!!✌

Physics

2 answers:

Nina [5.8K]3 years ago

7 0

Answer:

koj ruam zog

Explanation:

Alex73 [517]3 years ago

5 0

Answer:

the answer of 7th question

Make sure your dishwasher is full before you use it – running a half-empty dishwasher wastes large amounts of energy

Try to use a cooler temperature

Consider drying your clothes outside if it’s warm instead of using the dryer

Turn off the fan when you leave a room

Close your drapes or drop your window shades during the day.

Wash your clothes in cold water.

Wrap or cover foods and drinks in the refrigerator.

Always use the cold water faucet, unless you really want hot water.

the answer of 10th question

Static electricity is used in pollution control by applying a static charge to dirt particles in the air and then collecting those charged particles on a plate or collector of the opposite electrical charge. These devices are commonly known as “electrostatic precipitators.

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Em um centro de distribuição uma empilhadeira carrega uma caixa de 1000kg até o caminhão responsável pelo transporte desta carga

Yakvenalex [24]

Answer:

F = 592238.09 N

Explanation:

To find the mean force you first calculate the acceleration by using the following kinematic equation:

$v^2=v_o^2+2ax\\\\v_o=0m/s\\\\v=10km/h\\\\x=8.4m\\\\$

you do "a" the subject of the equation and replace the values of the other parameters:

$a=\frac{v^2}{2x}=\frac{10000m/s}{2(8.4m)}=595.23\frac{m}{s^2}$

next, the force, by using the second Newton law is:

$F=ma=(1000kg)(595.23\frac{m}{s^2})=595238.09\ N$

hence, the force is 592238.09 N

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TRANSLATION:

Para encontrar a força média, primeiro calcule a aceleração usando a seguinte equação cinemática:

você faz "a" o assunto da equação e substitui os valores dos outros parâmetros:

Em seguida, a força, usando a segunda lei de Newton, é:

portanto, a força é 592238.09 N

8 0

3 years ago

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following case

Murljashka [212]

Answer:

The answer is below

Explanation:

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the

cable for the following cases:

a. The load moves downward at a constant velocity

b. The load accelerates downward at a rate 0.4 m/s??

C. The load accelerates upward at a rate 0.4 m/s??

Solution:

Acceleration due to gravity (g) = 10 m/s²

a) Given that the mass of the crane (m) is 140 kg. If the load moves downward, the tension (T) is given by:

mg - T = ma

Since the load has a constant velocity, hence acceleration (a) = 0. Therefore:

mg - T = m(0)

mg - T = 0

T = mg

T = 140(10) = 1400 N

T = 1400 N

b) If the load moves downward, the tension (T) is given by:

mg - T = ma

T = mg - ma = m(g - a)

T = 140(10 - 0.4) = 140(9.96) = 134.4

T = 134.4 N

c) If the load moves upward, the tension (T) is given by:

T - mg = ma

T = ma + mg = m(a + g)

T = 140(0.4 + 10) = 140(10.4)

T = 145.6 N

2) To find the distance (s) if the load move from rest (u= 0) and accelerates for 20 seconds (t = 20). We use:

s = ut + (1/2)gt²

s = 0(20) + (1/2)(10)(20)²

s = 2000 m

7 0

3 years ago

Alpha Particles

UNO [17]

Alpha > Beta > Gamma

Explanation:

Alpha particles are the heaviest radiation whereas gamma rays are the lightest.

An alpha particle closely resembles a helium particle.

Beta particles are similar to electrons in nature

Gamma rays have no weight. They are just rays.

Alpha particles have a mass of 4.0012amu which is that of helium

Beta particles have a mass of 5.5 x 10⁻⁴ amu

Gamma rays have no mass.

Learn more:

Electromagnetic radiations brainly.com/question/6818046

#learnwithBrainly

7 0

3 years ago

Read 2 more answers

It is easier to to pull the bucket of water from well until it is inside the water but difficult out of water?why

Likurg_2 [28]

Gravity will affect both, the bucket and the water inside of it so the combined mass of the water and bucket will have higher weight

3 0

3 years ago

A 1.40 kg block is attached to a spring with spring constant 15.5 N/m . While the block is sitting at rest, a student hits it wi

slava [35]

Answer:

v = 3.08 m/s.

Explanation:

Given,

Initial velocity of the block = u = 43 cm/s = 0.43 m/s
mass of the block = m = 1.40 kg
spring constant = k = 15.5 N/m.
x = 0.650 m

At x = 0.650 m

Let 'a' be the acceleration of the block at x.

Total force due to the spring force on the blcok at x= kx

$\therefore F_s\ =\ kx\\\Rightarrow ma\ =\ kx\\\Rightarrow a\ =\ \dfrac{kx}{m}\\\Rightarrow a\ =\ \dfrac{15.5\times 0.650}{1.40}\\\Rightarrow a\ =\ 7.19\ m/s^2$

Hence the acceleration of the block at x is 7.19\ m/s^2.

Let 'v' be the velocity of the block at x.

From the kinematics,

$v^2\ =\ u^2\ +\ 2ax\\\Rightarrow v\ =\ \sqrt{u^2\ +\ 2ax}\\\Rightarrow v\ =\ \sqrt{0.43^2\ +\ 2\times 7.19\times 0.650}\\\Rightarrow v\ =\ 3.08\ m/s.$

Hence at the compression x = 0.650 m the velocity of the block is 3.08 m/s.

5 0

3 years ago

Answer all please!!!!!!!!!!✌​

Answer all please!!!!!!!!!!✌