determine the weight in newtons of a woman whose weight in pounds is 125. also, find her mass in slugs and in kilograms. DEtermi
1 answer:
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Answer:
The new pressure of the gas is 15.40 kPa.
Explanation:
Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. Mathematically this law indicates that the quotient between pressure and temperature is constant:
On the other hand, Boyle's law says that the volume occupied by a certain gaseous mass at constant temperature is inversely proportional to the pressure. This law is expressed mathematically as:
P*V=k
Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. Mathematically, this law says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
Studying an initial state 1 and a final state 2, it is fulfilled:
In this case:
- P1= 10 kPa
- V1= 200 L
- T1= 0 C= 273 K
- P2=?
- V2= 175 L
- T2= 95 C= 368 K
Replacing:
Solving:
P2= 15.40 kPa
<u><em>The new pressure of the gas is 15.40 kPa.</em></u>
Answer:
Time period, T = 1.98 seconds
Explanation:
It is given that,
Mass of the block, m = 300 g = 0.3 kg
Force constant of the spring, k = 3 N/m
Displacement in the block, x = 3 cm
Let T is the period of the motion of the block. The time period of the block is given by :
T = 1.98 seconds
So, the period of the motion of the block is 1.98 seconds. Hence, this is the required solution.
The figure is missing: find it in attachment.
a) (3i - 5j) N
First of all, we have to write each force as a vector with a direction:
- Force F1 points downward, so along the negative y-direction, so we can write it as
- Force F2 points to the right, so along the positive x-direction, so we can write it as
- Force F3 points to the left, so along the negative x-direction, so we can write it as
Now we can write the net force, by adding the three vectors and separating the x-component from the y-component:
b) 5.8 N
The magnitude of the net force can be calculated by applying Pythagorean's theorem on the components of the net force:
where
is the x-component
is the y-component
Substituting into the equation,
c)
The angle of the net force, measured with respect to the positive x-axis (counterclockwise), can be calculated by using the formula
where
is the x-component
is the y-component
Substituting into the equation, we find
d)
The acceleration can be found by using Newton's second law:
where
F is the net force on an object
m is its mass
a is the acceleration
For the object in the problem, we know
F = 5.8 N
m = 6.9 kg
Solving the equation for a, we find the magnitude of the acceleration:
