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Bogdan [553]
3 years ago
8

In this lab you will use a cart and track to explore various aspects of motion. You will measure and record the time it takes th

e cart to travel certain distances, and then complete some calculations. In the space below, write a scientific question that you will answer by doing this experiment.
Physics
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Answer:

How does an object's position and velocity change as the object accelerates?

Explanation:

Keith_Richards [23]3 years ago
3 0

It is given that by using track and cart we can record the time and the distance travelled and also the speed of the cart can be recorded. With all this data we can solve questions on the laws of motion.  

Like using the first law of motion we can determine the force of gravity acting on the cart that has moved a certain distance and the velocity or the speed of card has already been registered and since time is known putting the values in formula would help us calculate the gravitational pull acting on cart.

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Substances can undergo physical changes or chemical changes. what is the difference between these two kinds of changes
soldi70 [24.7K]
Physical changes are those change which just externally or physically change the state of the object . for example : water boils and evaporates... here the state is just changing from liquid to vapour while the composition is the same.

chemical changes are those which bring about a change in the composition of a substance. for example: burning of paper changes into ash .
8 0
3 years ago
Read 2 more answers
Whenever two Apollo astronauts were on the surface of the Moon, a third astronaut orbited the Moon. Assume the orbit to be circu
inysia [295]

Answer:

v  =  1,582 \ \frac{m}{s}

Explanation:

We know that for circular motion the centripetal acceleration a_c is:

a_c = \frac{v^2}{r}

where v is the speed and r is the radius.

The centripetal acceleration for the astronaut must be the gravitational acceleration due to the gravity, as there are no other force. So

a_c = 1.27 \frac{m}{s^2}.

The radius of the orbit must be the radius of the Moon, plus the 270 km above the surface

r = 1.7 * 10^6 \ m + 270  \ km

r = 1.7 * 10^6 \ m + 270 * 10^3 \ m

r = 1.7 * 10^6 \ m + 0.270 * 10^6 \ m

r = 1.97 * 10^6 \ m

We can obtain the speed as:

v^2  = a_c r

v  = \sqrt{a_c r}

v  = \sqrt{1.27 \frac{m}{s^2} * 1.97 * 10^6 \ m}

v  = \sqrt{ 2.509 \ 10^6 \ \frac{m^2}{s^2}}

v  =  1.582 \ 10^3 \ \frac{m}{s}

v  =  1,582 \ \frac{m}{s}

And this is the orbital speed.

7 0
3 years ago
The train traveled 500 kilometers north to Odessa in 2 hours . What’s the train’s speed ? What is the velocity ?
ElenaW [278]

Explanation:

Speed is distance over time.

500 km / 2 hr = 250 km/hr

Velocity is speed and direction.

250 km/hr north

7 0
3 years ago
What type of atom is K2CO3
My name is Ann [436]
<span>Potassium carbonate (K2C03) is white salt and is often </span>found damp. It is soluble in water which makes a strong concoction. Hope this helps.
4 0
3 years ago
Read 2 more answers
4. The Mariana trench is in the Pacific Ocean and has a depth of approximately 11,000 m. The density of seawater is approximatel
Alex73 [517]

Explanation:

It is known that relation between pressure and density is as follows.

            P = \rho gh

where,    P = pressure

     \rho = density

            g = acceleration due to gravity

            h = height

Putting the given values into the above formula as follows.

              P = \rho gh

                 = 1025 \times 9.8 \times 11000

                 = 110495000 Pa

Now, relation between pressure and force is as follows.

                P = \frac{F}{A}

or,            F = PA

                F = 110495000 \times \pi \times (0.1)^{2}

                   = 3.47 \times 10^{6} N

Thus, we can conclude that a force of 3.47 \times 10^{6} N can be  experienced at such depth.

3 0
3 years ago
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