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Bogdan [553]
2 years ago
8

In this lab you will use a cart and track to explore various aspects of motion. You will measure and record the time it takes th

e cart to travel certain distances, and then complete some calculations. In the space below, write a scientific question that you will answer by doing this experiment.
Physics
2 answers:
andreyandreev [35.5K]2 years ago
8 0

Answer:

How does an object's position and velocity change as the object accelerates?

Explanation:

Keith_Richards [23]2 years ago
3 0

It is given that by using track and cart we can record the time and the distance travelled and also the speed of the cart can be recorded. With all this data we can solve questions on the laws of motion.  

Like using the first law of motion we can determine the force of gravity acting on the cart that has moved a certain distance and the velocity or the speed of card has already been registered and since time is known putting the values in formula would help us calculate the gravitational pull acting on cart.

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When a high-mass star explodes, which of the following is left over in the center?
il63 [147K]
I would say option D, it depends on the size of the star
8 0
3 years ago
A projectile has an initial horizontal velocity of 34.0 M/s at the edge of a roof top. Find the horizontal and vertical componen
Sveta_85 [38]

Answer:

v_x=34 m/s

v_y=53.9\ m/s

Explanation:

<u>Horizontal Launch</u>

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

vx=v

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:

v_y=g.t

The horizontal component of the velocity is always the same:

v_x=34 m/s

The vertical component at t=5.5 s is:

v_y=9.8*5.5=53.9

v_y=53.9\ m/s

8 0
2 years ago
Is the earth's gravitational force on the sun larger than, smaller than, or equal to the sun's gravitational force on the earth?
Leona [35]

Answer:

The earth's gravitational force on the sun is equal to the sun's gravitational force on the earth

Explanation:

Newton's third law (law of action-reaction) states that:

"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"

In other words, when two objects exert a force on each other, then the magnitude of the two forces is the same (while the directions are opposite).

In this problem, we can call the Sun as "object A" and the Earth as "object B". According to Newton's third law, therefore, we can say that the gravitational force that the Earth exerts on the Sun is equal (in magnitude, and opposite in direction) to the gravitational force that the Sun exerts on the Earth.

6 0
3 years ago
1
Ray Of Light [21]

Acceleration = Force \ mass

0,375N/0,60kg=0.6ms-2

4 0
2 years ago
What type of country is described by low birth rates, lower infant mortality rates, and longer life expectancy?
Gala2k [10]
For the last one should be D.
8 0
3 years ago
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