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Convert the given temperatures from celsius to kelvin since we are dealing with gas.
To convert to kelvin, add 273.15 to the temperature in celsius.
T1 = 22 + 273.15 = 295.15 k
T2 = 4 + 273.15 = 277.15 k
V1 = 0.5 L
Let's find the final volume (V2).
To solve for V2 apply Charles Law formula below:
Answer:
Explanation:
0°Κ = -273.15°C = -459.67 °F
1 °K = 9/5 °F
a) 75.6 - 273.15 = -197.55 °C
b) -459.67 + 75.6(9/5) = -323.59 °F
Speed = (distance covered) / (time to cover the distance)
= (6.4 meters) / (4 minutes)
= (6.4/4) (meter/minute) = 1.6 meter per minute .
Answer: m∠P ≈ 46,42°
because using the law of sines in ΔPQR
=> sin 75°/ 4 = sin P/3
so ur friend is wrong due to confusion between edges
+) we have: sin 75°/4 = sin P/3
=> sin P = sin 75°/4 . 3 = (3√6 + 3√2)/16
=> m∠P ≈ 46,42°
Explanation:
Answer:
It should be 1 meter, but I'm no scientist.
Explanation: IDK