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OlgaM077 [116]
2 years ago
7

What is this answer? A B C OR D?

Mathematics
2 answers:
Delicious77 [7]2 years ago
4 0

Answer:

B I believe I'm a little rusty on math

Step-by-step explanation:

Pie2 years ago
3 0

Answer:

Two Solution

Step-by-step explanation:

bc im right

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laiz [17]

Answer:

Step-by-step explanation:

81 = 9 * 9 = 3 * 3 * 3 *3

8 = 2 * 2 * 2 *2

\sqrt{81 * 8 } = \sqrt{3*3*3*3*2*2*2}\\\\=3 * 3 * 2 \sqrt{2}\\\\= 18\sqrt{2}

6 0
3 years ago
Which data value has the highest frequency? 1 1/6 3 1/6 3/8 5/8
Marat540 [252]

Answer:

3 1/6

Step-by-step explanation:

To find the highest value, we have to evaluate each term individually,

1)  1 1/6 = 7/6 = 1.167

2) 3 1/6 = 19/6 = 3.16

3) 3/8 = 0.375

4) 5/8 = 0.625

Therefore, second data value (3 1/6) is highest.

 

8 0
3 years ago
There are four more women than men at a golf club.
marissa [1.9K]

Answer: I think its 4 + 2m

5 0
3 years ago
Help!!! this is due tomorrow!!!!!
SpyIntel [72]
It’s b
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8 0
3 years ago
XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3
nataly862011 [7]
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

5 0
3 years ago
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