Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F
N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:


∵ 
∵ 


∵ 
∵ 

F
N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F
N
Answer:
2.5*10^7 thank you
Step-by-step explanation:
thank you
Answer:
6(3d+2)
Step-by-step explanation:
12.T
13.F
14.F
15.F.
16.???(where is 16?:O)
17.T
18.T
19.T
20.???(where is 20?)
21.5
22.5
9514 1404 393
Answer:
24.885 in²
Step-by-step explanation:
Use the formula for the area of a triangle.
A = 1/2bh . . . . . . . where b is the base length and h is the height perpendicular to the base
A = 1/2(7.9 in)(6.3 in) = 24.885 in²
_____
<em>Additional comment</em>
The given side lengths cannot form a triangle, as the side shown as 14.7 is too long for the ends of the other segments to connect to. The attachment shows that side should be 11.97 in.