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faust18 [17]
2 years ago
14

Give the following number of protons, neutrons, and electrons in the following isotope:

Chemistry
1 answer:
valina [46]2 years ago
3 0

Answer:

47, 68, 47

Explanation:

Let's consider the following isotope: ¹¹⁵Ag.

If we look in the Periodic Table, the atomic number of Ag is 47, that is, silver has 47 protons.

Since ¹¹⁵Ag is neutral it must have the same number of protons that of electrons. Then, it also has 47 electrons.

The number 115 in ¹¹⁵Ag stands for the mass number, which is the sum of protons and neutrons. Then, the number of neutrons is:

p⁺ + n⁰ = 115

n⁰ = 115 - p⁺ = 115 - 47 = 68

The number of protons, neutrons, and electrons in ¹¹⁵Ag is: 47, 68, 47.

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Given the following, determine ΔG°f at 298 K for SnO. Sn(s) + SnO2(s) → 2SnO(s) ; ΔG° = 12.0 kJ at 298K
Virty [35]

Answer:

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.

Explanation:

Sn(s) + SnO_2(s)\rightarrow 2SnO(s), \Delta G_{f}^{o} = 12.0 kJ

\Delta G_{f,SnO_2}^{o}= -515.8kJ/mol

\Delta G_{f,Sn}^{o}= 0 kJ/mol

\Delta G_{f,SnO}^{o}=?

\Delta G_{f}^{o}=\sum ((\Delta G_{f}^{o})_ {products})-\sum ((\Delta G_{f}^{o})_ {reactants})

12.0 kJ=(2 mol\times \Delta G_{f,SnO}^{o})-(1mol\times 0 kJ/mol+1 mol\times -515.8 kJ/mol)

\Delta G_{f,SnO}^{o}=-251.9 kJ/mol

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.

3 0
3 years ago
1.Which element would most likely lose electrons to form positive ions when bonding with other elements?
wariber [46]

1) The element that will most likely lose electrons to form positive ions when bonding with other elements is rubidium (Rb).

2) The correct statement about sodium atoms is; "The sodium atom transfers electrons to the chlorine atoms to form ionic bonds."

3) Based on their location in the periodic table, nitrogen (N) and oxygen (O) are most likely to form covalent bonds with each other

4) Electronegativity is best described by the phrase; "the relative strength with which an element attracts electrons in a chemical bond"

Metals of group 1 and 2 are highly electropositive and are more likely to loose electrons in a bonding situation. Therefore, the element that will most likely lose electrons to form positive ions when bonding with other elements is rubidium (Rb).

Sodium chloride is an ionic compound. It is formed by transfer of electrons from sodium to chlorine. Sodium is highly electropositive while chlorine is highly electronegative. Therefore, sodium chloride is formed when sodium atom transfers electrons to the chlorine atoms to form ionic bonds.

Covalent bonds are formed between two nonmetals. Nitrogen and oxygen are non metals hence they form covalent bonds.

According to Linus Pauling, electronegativity refers to the ability of an element in a compound to draw electrons towards itself.

Learn more: brainly.com/question/14077687

8 0
3 years ago
List the 5 chemicals with the highest flash point. (In order, staring with the highest)
Volgvan

Answer:

Flash point of Lube Oil is around the 187°C mark, 

Flash point of Biodiesel of 130°C

Flash point of Diesel Ranging from 52° to 96°

8 0
3 years ago
What’s 0.517 in scientific notation?
Shkiper50 [21]

Answer:

5.17 × 10^-1

Explanation:

move the decimal to the right one space.

when you move the decimal to the right its exponent becomes a negative.

6 0
3 years ago
what happens when baking soda is mixed with vinegar a a new substance is formed B the substances are the same c but the baking s
Ray Of Light [21]

Answer:

NaHCO3 sodium bicarbonate is baking soda; added to the acetic acid, it forms sodium acetate (aqueous), CO2 gas & water. Remove the water & solid sodium acetate remains.

Explanation:

5 0
3 years ago
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