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Svetradugi [14.3K]
3 years ago
15

Qué concentración en % m/m tendrá una solución preparada con 20 g de NaCl (cloruro de sodio, sal común) y 200 g de agua?

Chemistry
1 answer:
alexgriva [62]3 years ago
4 0

Answer:

\%m/m = 10\,\%

Explanation:

El porcentaje masa a masa de la solución se obtiene al dividir la masa del cloruro de sodio por la masa del agua (The mass-mass percentage of solution is obtained by dividing the mass of sodium chloride by the mass of water):

\%m/m = \frac{20\,g}{200\,g}\times 100\,\%

\%m/m = 10\,\%

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Answer:

1. d. 84g

2. c. 77.4%

Explanation:

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The moles of Na (22.99g/mol) in 33g are:

33g * (1mol / 22.99g) = 1.435 moles Na = 1.435 moles NaCl must be produced.

The mass of NaCl is (Molar mass: 58.44g/mol):

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