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Svetradugi [14.3K]
3 years ago
15

Qué concentración en % m/m tendrá una solución preparada con 20 g de NaCl (cloruro de sodio, sal común) y 200 g de agua?

Chemistry
1 answer:
alexgriva [62]3 years ago
4 0

Answer:

\%m/m = 10\,\%

Explanation:

El porcentaje masa a masa de la solución se obtiene al dividir la masa del cloruro de sodio por la masa del agua (The mass-mass percentage of solution is obtained by dividing the mass of sodium chloride by the mass of water):

\%m/m = \frac{20\,g}{200\,g}\times 100\,\%

\%m/m = 10\,\%

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Can you please help me?
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Explanation:

The balanced equation for the reaction is given below:

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Find the volume of 200g of benzene, if the density of benzene is 0.88 g/mL.
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Answer:

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Explanation:

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volume =  \frac{mass}{density} \\

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