Answer:
1. d. 84g
2. c. 77.4%
Explanation:
1. Based on the reaction 2 moles of Na produce 2 moles of NaCl.
The moles of Na (22.99g/mol) in 33g are:
33g * (1mol / 22.99g) = 1.435 moles Na = 1.435 moles NaCl must be produced.
The mass of NaCl is (Molar mass: 58.44g/mol):
1.435moles * (58.44g / mol) = 84g
d. 84g
2. Percent yield is defined as 100 times the ratio between actual yield (65g) and theoretical yield (84g). The percent yield is:
65g / 84g * 100 =
c. 77.4%
the actual yield is the amount of Na₂CO₃ formed after carrying out the experiment
theoretical yield is the amount of Na₂CO₃ that is expected to be formed from the calculations
we need to first find the theoretical yield
2Na₂O₂ + 2CO₂ ---> 2Na₂CO₃ + O₂
molar ratio of Na₂O₂ to Na₂CO₃ is 2:2
number of Na₂O₂ moles reacted is equal to the number of Na₂CO₃ moles formed
number of Na₂O₂ moles reacted is - 7.80 g / 78 g/mol = 0.10 mol
therefore number of Na₂CO₃ moles formed is - 0.10 mol
mass of Na₂CO₃ expected to be formed is - 0.10 mol x 106 g/mol = 10.6 g
therefore theoretical yield is 10.6 g
percent yield = actual yield / theoretical yield x 100%
81.0 % = actual yield / 10.6 g x 100 %
actual yield = 10.6 x 0.81
actual yield = 8.59 g
therefore actual yield is 8.59 g
- The substance that made up of a particular mixture can be regarded as Solute and solvent
- A mixture can be regarded as material which is made up of more than one different Chemical substance or substances , whereby they are not chemically combined.
- Substance could be any matter such as <em>salt, rice, and or compounds</em>
- A mixture can be regarded as physical combination involving two or more substances whereby each entities identities are retained, then mixed in the form such as ;
- <em>solutions</em>
- <em> suspensions </em>
- <em> colloids</em>.
- A mixture could be in this form <em>(Solute + solvent = solution)</em>
Therefore, the substance that made up of a particular mixture can be regarded as <em>Solute and solvent</em>
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Redox Reaction is an ionic bond