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Brilliant_brown [7]
3 years ago
14

What are the respective roles of grb2 and sos in the activation of ras by egfr?

Chemistry
1 answer:
valina [46]3 years ago
5 0

Answer:

Role is defined below

Explanation:

A small GTP-binding protein, is an important module of the signal transduction pathway used by growth factors to initiate cell growth and differentiation. Cellular activation with growth factors such as epidermal growth factor (EGF) induces Ras to move from an inactive state linked to GDP to an active state linked to GTP. In recent times, a mixture of genetic and biochemical studies has resulted in the elucidation of a signaling pathway that leads from growth factor receptors to Ras. After joining EGF, the EGF receptor tyrosine kinase is activated, which leads to receptor auto phosphorylation in multiple tyrosine residues. Signaling proteins with homology domains Src 2 (SH2) then bind to these phosphorylated residues in tyrosine, initiating multiple signaling cascades. Distinct of these SH2 area proteins, Grb2, exists in the cytoplasm in a preformed complex with a second protein, Son of Sevenless (Sos), which can catalyze the Ras GTP / GDP exchange. After stimulation of the growth factor, the phosphorylated EGF receptor with tyrosine binds to the Grb2 / Sos complex and translocates it to the plasma membrane. It is believed that this translocation brings Sos closer to Ras, which leads to the activation of Ras. In dissimilarity, the insulin receptor does not bind Grb2 directly, but rather induces the tyrosine phosphorylation of two proteins, the substrate-1 insulin receptor and Shc, which bind to the Grb2 / Sos complex. Once Ras is activated, a cascade of protein kinases that are important in a myriad of growth factor responses is stimulated.

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The reaction A → B + C is known to be zero order in A with a rate constant of 5.0 × 10–2 mol/L·s at 25°C. An experiment was run
DerKrebs [107]

Answer:

D. 2.5 × 10–4 M

Explanation:

Data given in the question are;

rate constant of 5.0 × 10–2 mol/L·s

[A]0 = 1.0 × 10–3 M

5 × 10–3 sec

It was mentioned that the reaction is a zero order reaction. One interesting charaacteristics about zero order reactio is that the rate of reaction is indepenedent on the concentrations of the reactants.

This means in zero order reactions, we have;

Rate = Rate constant

Rate =  5.0 × 10–2 mol/L·s

What is the concentration of B after 5 × 10–3 sec?

Concentration = Rate * Time

Concentration = 5.0 × 10–2 * 5 × 10–3

Concentration = 2.5 × 10–4 M

Correct option = D

4 0
3 years ago
You have lost nearly 6 inches of top soil on your 200 acre field in the last 10 years. The problem seems to be getting even wors
qaws [65]
You could consider building an irrigation system.
6 0
3 years ago
Clasifica los siguientes elementos en metales, no metales, metaloides , o gases , nobles : flúor , azufre , nitrogeno , cloro ,
professor190 [17]

Answer:

<u>  Translation:</u>

Classify the following elements into metals, nonmetals, metalloids, or gases, noble : fluorine, sulfur, nitrogen, chlorine, magnesium, helium, sodium, bromine, silicon, tellurium.

  • Metals: magnesium and sodium.
  • Nonmetals: fluorine, chlorine, bromine, sulfur and nitrogen.
  • Metalloids: silicon and tellurium.
  • Noble gases: helium.

Explanation:

Metals: They occupy the left and central areas of the Periodic Table; therefore, they constitute a majority group of the elements.

Nonmetals: They are located in the upper right region of the Periodic Table.

Within the Periodic Table, the metalloids lie diagonally from boron to polonium. Items above on the right are nonmetals, and items below on the left are metals.

The noble gases are located in group 18 of the Periodic Table.

7 0
3 years ago
Read 2 more answers
Rewrite and Balance the Equation <br> N₂ + H₂ -&gt; NH3
Mars2501 [29]

Answer:N

2

+ 3

H

2

-----> 2N

H

3

Explanation:

N

2

+

H

2

-----> N

H

3

Let us balance this equation by counting the number of atoms on both sides of the arrow.

N

2

+

H

2

-----> N

H

3

N=2 , H=2 N=1, H=3

To balance the number of N atom on Right Hand Side (RHS) , I will add one molecule of N

H

3

on RHS

N

2

+

H

2

-----> 2N

H

3

N=2 , H=2 N=2 , H= 6

To balance the number of H atoms on Left Hand Side (LHS) , I will add two molecules of

H

2

on LHS

N

2

+ 3

H

2

-----> 2N

H

3

N=2 , H=6 N=2 , H= 6

Answer link

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3 years ago
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What intermolecular force involves non polar molecules
Zolol [24]

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www.ausetute.com.au/intermof.html


7 0
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