Which of these statements regarding real-time strategy games is true?

why does it not let me create a new account when i log out of this one and go to join now after i fill everything out it wont le

frozen [14]

Try linking an email to your account, if it doesn’t work select forgot your password and you should receive an email where you can re make or change your password to something easier to remember. Are you using the same email account every time, this may also be the reason, if it is the same email they will not allow you to reuse it and it should tell you the email is already in use. Hope this helped

5 0

4 years ago

What shortcut keys do i use to print something on my keyboard ?

romanna [79]

CTRL+P. It's usually pressed when you want to print something.

5 0

3 years ago

Read 2 more answers

Suppose that a 64MB system memory is built from 64 1MB RAM chips. How many address lines are needed to select one of the memory

alexdok [17]

Answer:

6 address lines

Explanation:

The computation of the number of address lines needed is shown below:

Given that

Total memory = 64MB

= $2^6MB$

= $2^{26} bytes$

Also we know that in 1MB RAM the number of chips is 6

So, the number of address lines is $2^{26} address$ i..e 26 address lines

And, the size of one chip is equivalent to 1 MB i.e. $2^{20} bytes$

For a single 1MB chips of RAM, the number of address lines is

$\frac{2^{26}}{2^{20}} \\\\= 2^6 address$

Therefore 6 address lines needed

5 0

3 years ago

You're a ticket agent for a commercial airline and responsible for checking the identification for each passenger before issuing

algol13

Answer:

Follows are the code to this question:

import java.util.*;//import package for user input

public class Main //defining class

{

public static void main(String[] as)//main method

{

boolean x,y,z;//defining boolean variable

Scanner ox= new Scanner(System.in);//create Scanner class object for user input

System.out.println("input value: "); //print message

x=ox.nextBoolean();//input value

y=ox.nextBoolean();//input value

z=ox.nextBoolean();//input value

System.out.println("Output: ");//print message

System.out.println(x || (y &&z));//use print method to check value and print its value

}

Output:

1)

input value:

true

false

Output:

true

2)

input value:

false

true

Output:

true

3)

input value:

false

Output:

false

Explanation:

In the given code, inside the class three boolean variable "x,y, and z" is declared, that uses the scanner class for input the value from the user end, and in the next print, the method is declared, that uses " OR and AND" gate for calculating the input value and print its value.

In the AND gate, when both conditions are true. it will print the value true, and in the OR gate, when one of the conditions is true, it will print the value true.

3 0

4 years ago

1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s

konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0

3 years ago