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3 years ago

A chef made 30 donuts in 60minutes how long would it take him to make 90donits

2 answers:

7 0

It would take him 180 mins or 3 hours.

This is because it takes him for 2 minutes to make 1 donut.

So 90 x 2 = 180 minutes or 3 hours.

Oksanka [162]3 years ago

5 0

30 donuts in 60 minutes
90 donuts ?

90 x 60 / 30 = 180 minutes

answer
180 minutes

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Lanie works part-time at Sweet Treats Catering. She earns $13.25 per hour and work 25 hours a

agasfer [191]

Answer:

Semi-monthly gross pay = $662.5

Step-by-step explanation:

Given:

Earning per hour = $13.25

Number of hours per week = 25 hours

Find:

Semi-monthly gross pay

Computation:

Assume two week in semi-month

So,

Total working hour = 2(25)

Total working hour = 50 hours

Semi-monthly gross pay = Total working hour × Earning per hour

Semi-monthly gross pay = 50 × 13.25

Semi-monthly gross pay = $662.5

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Which is the equation of a parabola with vertex (4,3) and directrix x = 6?

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Answer:

Step-by-step explanation:

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Mallory makes $10 per hour babysitting and $8 per hour working at the local grocery store. Last week she babysat for 6 hours. He

Aneli [31]

10x6=60 so 180-60=120 and 120 divided by 8 is 15 so the answer is 15 hours

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3 years ago

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Consecutive angles in a parallelogram are?

luda_lava [24]

Hello There!

Consecutive Angles In Parallelograms Are "Supplementary"

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1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

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