Answer:
Visible, or infrared lights
Answer:
A. 216.36 
B. 96.56 
Explanation:
Let
be the distance in first part.
= velocity × time
= 85 × 
= 49.58 km
Let
be the distance in first part.
= 130 km
Average velocity = 
When second leg of the trip is
A. Toward north
Average velocity =
}{Total time} [/tex]
Average velocity = 
Average velocity =216.36 
B. Toward south
Average velocity =
}{Total time} [/tex]
Average velocity = 
Average velocity =96.56 
Explanation:
It is given that,
Radius of loop, r = 78 mm = 0.078 m
Current, I = 114 A
(a) Magnetic field strength of the circular loop is given by :


B = 0.000918 T
or

(b) Energy density at the center of the loop is given by :



Hence, this is the required solution.
Answer:
The length of the trail = 22796 ft
Explanation:
From the ΔABC
AC = length of the trail = x
AB = 6100 - 600 = 5500 ft
Angle of inclination
= 15°



x = 22796 ft
Since x = AC = Length of the trail.
Therefore the length of the trail = 22796 ft