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3 years ago

How should you approach a dock when the wind or current is pushing you away from the dock?

Physics

1 answer:

erastova [34]3 years ago

8 0

Answer:

If the wind is offshore (blowing away from the dock), one should carefully approach the dock at a 20 to 30 degree angle. A bow line is then passed ashore and secured. In boats having an outboard, or inboard/outboard engine, the engine is turned towards the dock and put in reverse. This invariably will bring the stern into the dock.

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A certain brand of hot-dog cooker works by applying a potential difference of 120 V across opposite ends of a hot dog and allowi

ivanzaharov [21]

Answer:

The time it will take to cook three hot dogs simultaneously is 2.5 minutes

Explanation:

Here we have, the Energy of electric heating given by Joule heating that is;

P = IV = 120×10 = 1200 J/s = 1.2 kJ/s

Since the energy required to cook one hotdog = 60.0 kJ we have

Energy required to cook three hot dogs = 3 × 60.0 kJ = 180.0 kJ

Therefore, the time required to cook the three hot dogs is

(180.0 kJ)/(1.2 kJ/s) = 150 s

The time it takes to cook three hot dogs simultaneously is

150 seconds or 150/60 minutes which is 2 minutes 30 seconds or 2.5 minutes

5 0

3 years ago

A paintball is fired horizontally from a tower 45 m above the ground. If the paintball gun fires at 90 m/s… How long does it tak

ankoles [38]

Answer:

The time taken for the paint ball to hit the ground is $t = 2.143 \ s$

The distance of the landing point from the tower is $d = 192.86 \ m$

Explanation:

From the question we are told that

The height of the tower is $h = 45 \ m$

The speed of the paintball in the horizontal direction is $v_x = 90 \ m/s$

Generally from kinematic equation we have that

$h = ut + \frac{1}{2} at^2$

Here u is the initial velocity of the paintball in the vertical direction and the value is 0 m/s , this because the ball was fired horizontally

a is equivalent to $g = 9.8\ m/s^2$

t is the time taken for the paintball to hit the ground

$45 = 0* t + \frac{1}{2} 9.8 * t^2$

=> $t = 2.143 \ s$

Generally the distance of its landing position from the tower is

$d = v * t$

=> $d = 90 * 2.143$

=> $d = 192.86 \ m$

3 0

3 years ago

you drop a 2 kg book to a friend who stand on the ground at distance D=10.0 m below, if your friends out streched hand at distan

MariettaO [177]

Work is defined as force*displacement so total d=8.5m and force will be 2kg*g which is roughly 20N of force so W = 20N*8.5m=170J

For part b the gravitational energy is m*g*h so gravitational energy = 200J since 2kg*10 m/s^2 *10m so the change since the work is 170 j means total change is 170J and 30J is left

8 0

4 years ago

Read 2 more answers

Devise an exponential decay function that fits the given data, then answer the accompanying questions. Be sure to identify the

7nadin3 [17]

Answer:

22145.27733 ft

124984.76055 ft

Explanation:

The equation of pressure is

$P=P_0e^{-kh}$

where,

$P_0$ =Atmospheric pressure = 800 mbar

k = Constant

h = Altitude = 35000 ft

$P=\dfrac{1}{3}P_0$

$\dfrac{1}{3}P_0=P_0e^{-k35000}\\\Rightarrow \dfrac{1}{3}=e^{-k35000}\\\Rightarrow 3=e^{k35000}\\\Rightarrow ln3=k35000\\\Rightarrow k=\dfrac{ln3}{35000}\\\Rightarrow k=3.13\times 10^{-5}$

Now

$P=\dfrac{1}{2}P_0$

$ln2=kh\\\Rightarrow h=\dfrac{ln2}{k}\\\Rightarrow h=\dfrac{ln2}{3.13\times 10^{-5}}\\\Rightarrow h=22145.27733\ ft$

The altitude will be 22145.27733 ft

$P=0.02P_0$

$0.02P_0=P_0e^{-kh}\\\Rightarrow 0.02=e^{-3.13\times 10^{-5}h}\\\Rightarrow ln0.02=-3.13\times 10^{-5}h\\\Rightarrow h=\dfrac{ln0.02}{-3.13\times 10^{-5}}\\\Rightarrow h=124984.76055\ ft$

The elevation is 124984.76055 ft

6 0

3 years ago

Which type of electromagnetic waves have longer wavelengths that the waves that make up visible light.

Inessa [10]

Answer:

radiation

Explanation:

4 0

4 years ago

Read 2 more answers