Question

MgCl2 (aq) + K2SO4 (aq) --> 2KCl (aq) + MgSO4 (s)

Answer 1

Answer:

$\boxed {\boxed {\sf 9.6 \ mol \ KCl}}$

Explanation:

We must use stoichiometry to solve this, which is the calculation of reactants and products in a reaction using ratios.

Let's analyze the reaction given.

$MgCl_2 _{(aq)} + K_2SO_4 _{(aq)} \rightarrow 2KCl _{(aq)} + MgSO_4 _{(s)}$

Now, look at the coefficients, or numbers in front of the molecule formulas. If there isn't a coefficient, then a 1 is implied.

We want to find how many moles of potassium chloride (KCl) are produced from 4.8 moles of magnesium chloride (MgCl₂). Check the coefficients for these molecules.

• MgCl₂: no coefficient= coefficient of 1
• KCl: coefficient of 2

The coefficient represents the number of moles. Therefore, 1 mole of magnesium chloride produces 2 moles of potassium chloride. We can set up a ratio using this information.

$\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}$

Multiply by the given number of moles of magnesium chloride: 4.8

$4.8 \ mol \ MgCl_2 *\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}$

Flip the ratio so the moles of magnesium chloride cancel out.

$4.8 \ mol \ MgCl_2 *\frac {2 \ mol \ KCl} { 1 \ mol \ MgCl_2}$

$4.8 *\frac {2 \ mol \ KCl} { 1 \ } }$

$4.8 * {2 \ mol \ KCl}$

$9.6 \ mol \ KCl$

9.6 moles of potassium chloride are produced from 4.8 moles of magnesium chloride.