Question

Question 1 (5 points)

Answer 1

Answer:

The volume of ammonia produced by 4.2 L of hydrogen and excess nitrogen is 2.8 L.

Explanation:

Given data:

Volume of H₂ = 4.2 L

Volume of NH₃ produced = ?

Solution:

First of all we will write the balance chemical equation:

N₂ + 3H₂    →   2NH₃

Hydrogen is limiting reactant and volume ratio is,

                         H₂           :       NH₃

                         3             :         2

                         4.2         :           2/3 × 4.2 =  2.8 L

The volume of ammonia produced by 4.2 L of hydrogen and excess nitrogen is 2.8 L.