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Margarita [4]
3 years ago
14

Question 1 (5 points)

Chemistry
1 answer:
GuDViN [60]3 years ago
6 0

Answer:

The volume of ammonia produced by 4.2 L of hydrogen and excess nitrogen is 2.8 L.

Explanation:

Given data:

Volume of H₂ = 4.2 L

Volume of NH₃ produced = ?

Solution:

First of all we will write the balance chemical equation:

N₂ + 3H₂    →   2NH₃

Hydrogen is limiting reactant and volume ratio is,

                         H₂           :       NH₃

                         3             :         2

                         4.2         :           2/3 × 4.2 =  2.8 L

The volume of ammonia produced by 4.2 L of hydrogen and excess nitrogen is 2.8 L.

                         

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Solution:

Step 1: Convert mm³ into L;


As,


                                            1 mm³  =  1.0 × 10⁻⁶ Liters


So,


                                         0.1 mm³  =  X  Liters


Solving for X,


                       X  =  (0.1 mm³ × 1.0 × 10⁻⁶ Liters) ÷ 1 mm³


                       X  =  1.0 × 10⁻⁷ Liters


Step 2: Calculate No. of RBC's in 5 Liter Blood:


As given


                        1.0 × 10⁻⁷ Liters Blood contains  =  6000 RBC's


So,


                         5.0 Liters of Blood will contain  =  X  RBC's


Solving for X,


                      X  =  (5.0 Liters × 6000 RBC's) ÷ 1.0 × 10⁻⁷ Liters


                      X  =  3.0 × 10¹¹ RBC's


Or,


                     X  =  3E11 RBC's



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