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sdas [7]
3 years ago
5

What is the difference between speed and velocity?

Chemistry
1 answer:
Amanda [17]3 years ago
6 0

Answer:

(B) direction

Explanation: Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

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What determines which element an atom is?
Lana71 [14]
C) number of protons.
4 0
3 years ago
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Please help me will mark brainliest
LuckyWell [14K]

Answer:

accretion  

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the coming together and cohesion of matter under the influence of gravitation to form larger bodies.

8 0
2 years ago
5.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the
cupoosta [38]

Answer: Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

Explanation:

To calculate the entalpy, we use the equation:

q=mc\Delta T

where,

q = heat absorbed by water = ?

m = mass of water = {\text {volume of water}}\times {\text {density of water}}=100.0ml\times 1.00g/ml=100.0g

c = heat capacity of water = 4.186 J/g°C

\Delta T= change in temperature = 6.70^0C

q=100.0g\times 4.184J/g^0C\times 6.70^0C=2803.3J=2.8033kJ

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

The heat absorbed by water will be equal to heat released by MgSO_4

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 5.11 g

Molar mass  = 120 g/mol

Putting values in above equation, we get:

\text{Moles of }MgSO_4=\frac{5.11g}{120g/mol}=0.042mol

0.042 moles of MgSO_4 releases = 2.8033 kJ

1 mole of MgSO_4 releases = \frac{2.8033 kJ}{0.042}\times 1=66.7kJ

Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

3 0
3 years ago
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It's a double replacement reaction, so
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Ca3(PO4)2
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Expalin subshells and orbitals
Vadim26 [7]

Answer:

E

Explanation:

8 0
3 years ago
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