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Answer:
cinnamic acid - 150 mg
cis-stilbene - 100 μL
trans- stilbene - 100 mg
pyridinium tribromide - 200-385 mg
For this data:
moles of cinnamic acid = 0.150 g/148.16 g/mol = 0.001 mols
Theoretical mass of dibromoproduct formed = 0.001 mol x 307.97 g/mol = 0.312 g
cis-stilbene (100 ul = 0.1 ml)
moles of cis-stilbene = 0.1 ml x 1.01 g/mol/180.25 g/mol = 0.00056 mols
Theoretical mass of dibromoproduct formed = 0.00056 mol x 340.05 g/mol = 0.19 g
trans-stilbene
moles of tran-stilbene = 0.1 g/180.25 g/mol = 0.00055 mols
Theoretical mass of dibromoproduct formed = 0.00055 mol x 340.05 g/mol = 0.19 g
Explanation:
Since Lutetium-177 is a beta and gamma emitter, the daughter nuclide produced from the decay of this radioisotope is 177Hf.
Beta emission of a radioisotope yields a daughter nuclide whose amass number is the same as that of its parent nucleus but its atomic number is greater is greater than that of the parent nucleus by 1 unit.
Also, gamma emission does not lead to any change in the mass number of atomic number of the daughter nucleus produced.
Hence, the stable daughter nuclide, 177Hf is produced.
Learn more: brainly.com/question/1770619