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dem82 [27]
3 years ago
14

A 18.00 g g milk chocolate bar is found to contain 11.00 g g of sugar.1. How many milligrams of sugar does the milk chocolate ba

r contain?2. What will be the amount of sugar in milligrams if the size of the milk chocolate bar is reduced from 18.00 g to 4.000 g ? Express your answer in milligrams to four significant figures.
Chemistry
1 answer:
horrorfan [7]3 years ago
6 0

Answer:

1. 1.100x10⁴mg

2. 2444mg

Explanation:

1. The 18.00g milk chocolate bar contain 11.00g of sugar. In miligrams:

11.00g * (1000mg / 1g) = 1.100x10⁴mg

2. If a bar of 18.00g contain 11.00g of sugar, a bar of 4.000g will contain:}

4.000g bar * (11.00g / 18.00g)  = 2.444g of sugar.

In miligrams:

2.444g * (1000mg / 1g) = 2444mg

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1. When you first opened the bottle of coke the pressure of gas in the coke (increased/decreased) and the dissolved gas( stays i
Serga [27]

Answer:

1. When you first opened the bottle of coke the pressure of gas in the coke (increased) and the dissolved gas(leaves) the coke. 2. When you placed the coke in hot water , the pressure of gas in the coke (increased) and the dissolved gas(leaves) the coke 3. Therefore to increase the solubility of a gas in a liquid ( that is to make a gas more soluble in a liquid.

Explanation:

Hope it helps.

3 0
3 years ago
How many reactant molecules and product gas molecules are in this equation?
Mice21 [21]

Answer:

N₂  = 6.022 × 10²³ molecules

H₂ = 18.066 × 10²³ molecules

NH₃ = 12.044 × 10²³ molecules

Explanation:

Chemical equation;

N₂ + 3H₂     →  2NH₃

It can be seen that there are one mole of nitrogen three mole of hydrogen and two moles of ammonia are present in this equation. The number of molecules of reactant and product would be calculated by using Avogadro number.

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

Number of molecules of nitrogen gas:

1 mol = 6.022 × 10²³ molecules

Number of molecules of hydrogen:

3 mol × 6.022 × 10²³ molecules/ 1 mol

18.066 × 10²³ molecules

Number of molecules of ammonia:

2 mol × 6.022 × 10²³ molecules/ 1 mol

12.044 × 10²³ molecules

6 0
3 years ago
It takes 2 g of chlorine to sanitize 1,000,000g of water. How much chlorine will it take to sanitize a 40,000-gallon pool? ( 1 g
dimulka [17.4K]

Answer:

0.1g (Gallon) of chlorine

Explanation:

<u>Formula</u>

1 gallon = 3.7L; the density of water is 1.0g/ml

<u>Given</u>

2g (gallon) of chlorine to sanitize = 1,000,000g (gallon) of water

<u>Solve</u>

If 2g (gallon) chlorine = 1,000,000g (gallon)

∴, ? chlorine = 40,000

The First step; set up an equation

1000000/2 = 40000/?

The Next step; divide 1 million to 2

1000000 ÷ 2 = 500000

Then, divide the result by 40000

40000 ÷ 500000 = 0.08

In the nearest unit that is 0.1

Therefore, it will take 0.1g (gallon) of chlorine to sanitize a 40,000-gallon pool.

7 0
2 years ago
Read 2 more answers
The race car sped into the turn as it went around the track.
e-lub [12.9K]

Answer:

B or C , not sure though

Explanation:

7 0
3 years ago
How would you prepare a 1 L solution of 3 M MgO?
oksano4ka [1.4K]

Answer:  175.35g

Explanation:  A 3 M solution has 3 moles of solute per litre.

The mass of one mole of NaCl equals the MW of NaCl MW =  35.45 + 23 =58.45 g/mol

The mass of 3 moles is 58.45 g/mol ×3 mol=175.35 g NaCl  or  200 g rounded to one sigfig.

8 0
3 years ago
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