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dem82 [27]
3 years ago
14

A 18.00 g g milk chocolate bar is found to contain 11.00 g g of sugar.1. How many milligrams of sugar does the milk chocolate ba

r contain?2. What will be the amount of sugar in milligrams if the size of the milk chocolate bar is reduced from 18.00 g to 4.000 g ? Express your answer in milligrams to four significant figures.
Chemistry
1 answer:
horrorfan [7]3 years ago
6 0

Answer:

1. 1.100x10⁴mg

2. 2444mg

Explanation:

1. The 18.00g milk chocolate bar contain 11.00g of sugar. In miligrams:

11.00g * (1000mg / 1g) = 1.100x10⁴mg

2. If a bar of 18.00g contain 11.00g of sugar, a bar of 4.000g will contain:}

4.000g bar * (11.00g / 18.00g)  = 2.444g of sugar.

In miligrams:

2.444g * (1000mg / 1g) = 2444mg

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timofeeve [1]

Answer:

20.3 kJ of heat is absorbed when 9.00 g of steam condenses to liquid water.

Explanation:

Heat is being consumed during vaporization and heat is being released during condensation.

To vaporize 1 mol of water, 40.66 kJ of heat is being consumed.

Molar mass of water = 18.02 g/mol

Hence, to vaporize 18.02 g of water , 40.66 kJ of heat is being consumed.

So, to vaporize 9.00 g of water, (\frac{40.66}{18.02}\times 9.00)kJ of heat or 20.3 kJ of heat is being consumed

As condensation is a reverse process of vaporization therefore 20.3 kJ of heat is absorbed when 9.00 g of steam condenses to liquid water.

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3 years ago
Stirring a liquid while you are mixing in another ingredient speeds up the rate of dissolving. Question 13 options: True False
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Answer:

true

Explanation:

This is because it helps distribute the particles that are being dissolved. 

8 0
3 years ago
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An iron block of mass 18 kg is heated from 285 K to 318 K. If 267.3 kJ is required, what is the specific heat of iron? A. 450.00
valkas [14]

Answer:

  • <u>Option A. 450.00</u>

Explanation:

<u>1) Data:</u>

a) m = 18 kg

b) T₁ = 285 K

c) T₂ = 318 K

d) Q = 267.3 kJ

e) S = ?

<u>2) Principles and equations</u>

The specific heat of a substance is the amount of heat energy absorbed to increase the temperature of certain amount (gram, kg, or moles, depending on the definition or units) of the substance in 1 ° C or 1 K.

The mathematical relation between the specific heat and the heat energy absorbed is:

  • Q = m × S × ΔT

Where,

  • Q is the heat absorbed,
  • S is the specific heat, and
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<u>3) Solution:</u>

<u>a) Substitute the data into the equation:</u>

  • 267.3 kJ = 18 kg × S × (318 K - 285 K)

<u>b) Solve for S and compute:</u>

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The options have not units, but I notice that the first answer is 1,000 times the answer I obtained, so I will make a conversion of units.

<u>c) Convert to J /( kg . k):</u>

  • 0.45 kJ / (Kg . K) × 1,000 J / kJ = 450 J / (kg . K)

Now we can see that the option A is is the answer, assuming the units.

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