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lutik1710 [3]
3 years ago
6

1.Compare how waves are used to send information.

Physics
1 answer:
jeyben [28]3 years ago
8 0

Answer:

1:Radio waves are used to carry satellite signals. These waves travel at 300,000 km/s (the speed of light).

2:The standard methods of communication are speaking or writing by a sender and listening or reading the receiver. Most communication is oral, with one party speaking and others listening. ... A mixed message occurs when a person's words communicate one message, while nonverbally, he or she is communicating something else.

3: Today means of communication has increased such a lot that we can receive or send messages from or to far off places. Various means of communication which we use in the modern world are Posts and Telegraphs, Telephone, Radio and Television, Telex, Fax, Pagers, Email, Newspapers and cinema.

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Electrically charged sunspot gases which escape the sun's chromosphere and enter the earth's atmosphere near the magnetic north
Kisachek [45]

Answer:

Northern Lights ( Aurora Borealis)

Explanation:

When the electricaly charged sunspot gases (they are named a solar wind) escape the sun's chromosphere and penetrates from the earth magnetic sheild which is called earth's magnetosphere then upon there interaction with atoms and molecules of our atmosphere there are little bursts of photons in the form of light which made up these northern lights.

6 0
3 years ago
The energy that is released in a chemical reaction is _____________ the energy in the bonds of the reactants.
Rina8888 [55]
<em>the energy that is released in the chemical reactions is the exothermic energy ( stored ) in the bonds of reactants... :)</em>
6 0
4 years ago
Which measure of dispersion indicates the extent to which each individual score in a data set varies from the mean of that set?
vichka [17]

Answer:

Option 2 - Standard deviation

Explanation:

To find : Which measure of dispersion indicates the extent to which each individual score in a data set varies from the mean of that set?

Solution :

Standard deviation is defined as,

  • It is a mathematical measure that is used to evaluate the difference between the mean value of a set of number and each value in the group.
  • It is calculated as the square root of variance by determining the variation between each data point relative to the mean.

The measure of dispersion that indicates how much scores in a sample vary around the mean of the sample is the standard deviation.

Therefore, option 2 is correct.

3 0
3 years ago
This scientist focused his study on planetary motion. One of his laws is the planets orbit the Sun in elliptical patterns.
Savatey [412]
I believe that since Kepler focused his studies the rotation of the planets, and the stars, that he is the one who developed the law, which is called the first law of planetary motion.
8 0
3 years ago
In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.
BartSMP [9]

Answer:

The value of g in Kepler-12b is 3.85 m/s^{2}

Explanation:

To determine the value of g at Kepler-12b it is necessary to combine the equation of the weight and the equation for the Universal law of gravity:

W = m.g  (1)

Where m is the mass and g is the value of the gravity

F = G \frac{M.m}{R^{2}}  (2)

Equation (1) and equation (2) will be equal, since the weight is a force acting on the object as a consequence of gravity:

m.g = G \frac{M.m}{R^{2}}  (3)

Then g will be isolated from equation 3:

g = G \frac{M.m}{m.R^{2}}

g = \frac{G.M}{R^{2}}  (4)

The radius of Jupiter has a value of 69911000 meters, so its diameter can be determined by:

d = 2R (5)

Where d and R are the diameter and radius of Jupiter

d_{jupiter} = 2(69911000 m)

d_{jupiter} = 139822000 m

Procedure for finding the radius of Kepler-12b:

For the case of Kepler-12b it has a diameter that is 1.7 times that of Jupiter

d_{Kepler-12b} = 1.7(d_{jupiter})

d_{Kepler-12b} = 1.7(139822000 m)

d_{Kepler-12b} = 237697400 m

By means of equation 5 the radius of Kepler-12b can be known:

R_{Kepler-12b} = \frac{d}{2}

R_{Kepler-12b} = \frac{237697400 m}{2}

R_{Kepler-12b} = 118848700 m

Procedure for finding the mass of Kepler-12b:

The mass of Jupiter has a value of 1.898x10^{27} kilograms

For the case of Kepler-12b it has a mass that is 0.43 times that of jupiter

m_{Kepler-12b} = 0.43(m_{jupiter})

m_{Kepler-12b} = 0.43(1.898x10^{27} Kg)

m_{Kepler-12b} = 8.161x10^{26} Kg

The value of g in Kepler-12b can be found by replacing its radius and mass in equation 4:

g = \frac{(6.67x10^{-11} N.m^{2}/Kg^{2})(8.161x10^{26} Kg)}{(118848700 m)^{2}}

g = 3.85 m/s^{2}

Hence, in Kepler-12b the gravity has a value of 3.85 m/s^{2}

8 0
3 years ago
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