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3 years ago

The rate at which energy is transferred is called a. joules. b. power. c. work. d. time.

Physics

2 answers:

Marrrta [24]3 years ago

7 0

B. Power
I hope this helps you, have a great day!

Molodets [167]3 years ago

6 0

B. Power.
___________

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What is rain, is it water, gas, solid, what is it?

Elden [556K]

Answer:

rain is water because it's a liquid

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3 years ago

Suppose that the sun shrank in size but that its mass remained the same. What would happen to the orbit of the earth?

Minchanka [31]

Answer:

Nothing

Explanation:

The radius of the orbit of the Earth does not depend on the radius of the sun.

In fact, the gravitational attraction between the Earth and the Sun provides the centripetal force that keeps the Earth in orbit:

$G\frac{Mm}{r^2} = m\frac{v^2}{r}$

where

G is the gravitational constant

M is the mass of the sun

m is the mass of the Earth

r is the radius of the orbit of the Earth

v is the orbital speed of the earth

Re-arranging the equation for r:

$r=\frac{GM}{v^2}$

Also,

$v=\omega r$

where $\omega$ is the angular velocity of the Earth's orbit. So we can rewrite the equation as

$r=\frac{GM}{\omega^2 r^2}\\r^3 = \frac{GM}{\omega^2}$

As we see, the radius of the orbit of the Earth, r, does not depend on the mass of the Sun, so if the sun shrank in size, the orbit remains the same.

6 0

3 years ago

Rutherford discovered the nucleus of the atom by firing a particles at gold foil. An a particle has a charge of q = +2e and a ma

Readme [11.4K]

Answer: $r_0=3.037\times 10^{-14}m$

Explanation:

Given

charge on alpha particle=+2e

mass of alpha particle= $6.64\times 10^{-27}$ kg

Charge on gold nucleus=+79e

Velocity at r=1m is $1.9\times 10^{7}$

Using Energy conservation

Kinetic energy of particle will be converting to Potential energy as it approaches to nucleus

therefore

$\frac{1}{2}mv^2+U_{r=1m}=U_{closest\ to\ nucleus}$

$\frac{1}{2}\left ( 6.64\times 10^{-27}\right )\left ( 1.9\times 10^{7}^2\right )+\frac{K\left ( 2e\right )\left ( 79e\right )}{1}=\frac{K\left ( 2e\right )\left ( 79e\right )}{r_0}$

$\frac{1}{2}\left ( 6.64\times 10^{-27}\right )\left ( 1.9\times 10^{7}^2\right )=\frac{9\times 10^9\times 158\times \left ( 1.6\times 10^{-19}\right )}{y}\left [\frac{1}{r_0}-\frac{1}{1}\right ]$

on solving we get

$\frac{1}{r_0}=3.292\times 10^{13}$

$r_0=3.037\times 10^{-14}m$

8 0

3 years ago

A ball with 100 J of PE is released from a height of 10 m. What will be the KE of the ball at 5

harkovskaia [24]

Answer:

The kinetic energy is: 50[J]

Explanation:

The ball is having a potential energy of 100 [J], therefore

PE = [J]

The elevation is 10 [m], and at this point the ball is having only potential energy, the kinetic energy is zero.

$E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\$

In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.

When the elevation is 5 [m], we have a potential energy of

$P_{e} =m*g*h\\P_{e} =1.01*9.81*5\\\\P_{e} = 50 [J]\\$

This energy is equal to the kinetic energy, therefore

Ke= 50 [J]

8 0

3 years ago

Cold water will warm to room temperature faster in a: a) Black pot

Viktor [21]

Answer:

black pot

Explanation:

option a is correct

Cold water will warm to room temperature faster in a Black pot as we know that Black surfaces and good absorbers of heat in comparison to other surfaces. Moreover, Silver a good reflector of heat. It reflects most of heat incident on it, the cold water will take longer time to come the room temperature in Silver pot.

8 0

4 years ago