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yawa3891 [41]
3 years ago
9

What is the purpose of an experiment design?

Physics
1 answer:
Eddi Din [679]3 years ago
5 0
An experimental design is used to assign variables for testing. In contrast to a control design where nothing is changed, the experimental design allows you to test various new inputs to see how they would vary from the original results.
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Which of the following describes an element?
bixtya [17]

Answer:

A substance made of two or more types of atoms

Explanation:

8 0
2 years ago
A pendulum takes 10 seconds to swing through 2 complete cycles what is it’s period and frequency
Orlov [11]

its period should be the amount it takes to cycle from cycle to cycle so it would be 10 and your frequency would have to be calculated by taking 10 and dividing by 2 since that is how many cycles you have done so your frequency is 5


plz mark me brainliest

7 0
3 years ago
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How long would it take a drag racer to increase her speed from 10.m/s to 20 m/s if her car accelerates at a uniform rate of 15 m
garik1379 [7]
It would take about 2 thirds of a second or .66666666 repeating of a second. please give brainliest?
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3 years ago
A ball of mass 0.500 kg is carefully balanced on a shelf that is 2.70 m above the ground. What is its gravitational potential en
ratelena [41]

Answer:

The gravitational potential energy of the ball is 13.23 J.

Explanation:

Given;

mass of the ball, m = 0.5 kg

height of the shelf, h = 2.7 m

The gravitational potential energy is given by;

P.E = mgh

where;

m is mass of the ball

g is acceleration due to gravity = 9.8 m/s²

h is height of the ball

Substitute the givens and solve for gravitational potential energy;

PE = (0.5 x 9.8 x 2.7)

P.E = 13.23 J

Therefore, the gravitational potential energy of the ball is 13.23 J.

8 0
3 years ago
A 50.0-kg crate is being pulled along a horizontal smooth surface. The pulling force is 10.0 n and is directed 20.0° above the h
steposvetlana [31]

Answer:

0.188 m/s^2

Explanation:

Assuming the crate does not lift above the ground and remains along the floor, then its acceleration will be in the horizontal direction. Therefore, we can use Newton's second law to find its acceleration:

F_x = ma_x

where

F_x is the net force on the crate along the x-direction

m is the mass of the crate

a_x is the acceleration

Here we have:

m = 50.0 kg

F_x = F cos \theta = (10.0 N)(cos 20.0^{\circ})=9.4 N is the component of the pulling force along the horizontal direction

Solving for the acceleration,

a_x = \frac{F_x}{m}=\frac{9.4}{50.0}=0.188 m/s^2

6 0
4 years ago
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