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1 year ago

Calculate the weight of a 6 kg pizza.

Physics

2 answers:

Yuliya22 [10]1 year ago

8 0

13.23 pounds? if you are asking for it to be translated into pound sorry if that’s not what your looking for

In-s [12.5K]1 year ago

3 0

Answer:

by the question there is already given a weight of pizza. so its weight is 6kg

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Convert 0.700 atm of pressure to its equivalent in millimeters of mercury.

inna [77]

Answer:

532 millimeters of mercury

Explanation:

In order to convert the pressure from atm to millimeters of mercury (mm Hg), we should remind the conversion factor between the two units:

1 atm = 760 mm Hg

Therefore, we can solve the problem by setting up the following proportion:

$1 atm : 760 mmHg = 0.700 atm : x$

Solving for x, we find

$x=\frac{(760 mmHg)(0.700 atm)}{1 atm}=532 mmHg$

5 0

3 years ago

A planet exerts a gravitational force of magnitude 4e22 N on a star. If the planet were 3 times closer to the star (that is, if

Alex_Xolod [135]

Answer:

$3.6\times10^{23} N$

Explanation:

$F=\frac{GmM}{r^2}=4\times10^{22} N$

$F'=\frac{GmM}{(r/3)^2}=9\frac{GmM}{r^2}=9\times4\times10^{22}=3.6\times10^{23} N$

7 0

1 year ago

With what velocity Must a 0.53 kg softball be moving to be equal to the momentum of a 0.31 kg baseball moving at 21 m/s

vladimir2022 [97]

Answer:12.28m/s

Explanation:

momentum of baseball =mass of baseball x velocity of baseball

Momentum of baseball =0.31x21

Momentum of baseball =6.51kgm/s

For a softball to have same momentum with the baseball we can say :momentum of baseball =mass of softball x velocity of softball

6.51=0.53 x velocity of softball

Velocity of softball =6.51/0.53

Velocity of softball =12.28m/s

3 0

3 years ago

Two objects gravitationally attract with a force of 100 N. If the mass of one object is doubled and the mass of the other object

barxatty [35]

Hello!

Recall the equation for gravitational force:
$F_g = \frac{Gm_1m_2}{r^2}$

Fg = Force of gravity (N)
G = Gravitational constant

m1, m2 = masses of objects (kg)
r = distance between the objects' center of masses (m)

There is a DIRECT relationship between mass and gravitational force.

We are given:
$F_g = 100N$

If we were to double one mass and triple another, according to the equation:
$F'_g = \frac{G(2m_1)(3m_2)}{r^2} = 6(\frac{G(m_1)(m_2)}{r^2}) = 6F_g$

Thus:
$6 * F_g = 6 * 100 = \boxed{600N}$

5 0

2 years ago

A scientist at a space research center is doing research on near-Earth objects and determining the kinetic energy of a theoretic

Marysya12 [62]

<span>its kinetic energy is 7350kJ
</span>

Kinetic energy is given as = $\frac{1}{2} mv^{2}$

Now, m = 12 gms = 0.012 kg
And, velocity = 35 kilometers/second = 35000 m/sec

Kinetic energy is given as = $\frac{1}{2} 0.012 kg * 35000*35000 m/[tex] s^{2}$
= 6 $10^{-2}$ ×1225 × $10^{6}$ m/ $s^{2}$
= 7350 kJ

6 0

3 years ago

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