Answer:
a = g
Explanation:
in this scenario, the diver is free-falling, hence his acceleration is equal to the pull of gravity
Answer:
a) t=0.9935s
b) d = 6.95m
c) Hmax=2.1m
d) Vf = (9.009,-6.48) m/s
Explanation:
First of all, the we calculate the components of the initial velocity:
For the time of the jump:
Solving the quadratic equation for t, we get:
t = 0.9935s
For the distance of her impact, we will need the time we just calculated:
To know the maximum height:
Using this value, we calculate the maximum height:
Finally, for the final velocity, we use the time of the jump t=0.9935s:
Answer:
A) μ = A.m²
B) z = 0.46m
Explanation:
A) Magnetic dipole moment of a coil is given by; μ = NIA
Where;
N is number of turns of coil
I is current in wire
A is area
We are given
N = 300 turns; I = 4A ; d =5cm = 0.05m
Area = πd²/4 = π(0.05)²/4 = 0.001963
So,
μ = 300 x 4 x 0.001963 = 2.36 A.m².
B) The magnetic field at a distance z along the coils perpendicular central axis is parallel to the axis and is given by;
B = (μ_o•μ)/(2π•z³)
Let's make z the subject ;
z = [(μ_o•μ)/(2π•B)] ^(⅓)
Where u_o is vacuum permiability with a value of 4π x 10^(-7) H
Also, B = 5 mT = 5 x 10^(-6) T
Thus,
z = [ (4π x 10^(-7)•2.36)/(2π•5 x 10^(-6))]^(⅓)
Solving this gives; z = 0.46m =
Answer:
(D) all of the above
Explanation:
All of the choices describe matter.
Indeed because some leave headlights off and ignore that fact since there are street lights around.