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a_sh-v [17]
3 years ago
7

Which of the following is a characteristic of a weak acid?

Chemistry
2 answers:
mixas84 [53]3 years ago
6 0

Answer:

A,B,C,D

Explanation:

all of the above : )

if you had to go with a certain answer go with C im most sure of

A weak acid will not completely dissociate in water due to strong forces

snow_lady [41]3 years ago
4 0

Answer:

It does not dissociate completely in water.

or

It completely dissociates in water.

Explanation:

for      a p e x

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In the titration of 50.0 mL of HCl of unknown concentration, the phenolphthalein indicator present in the colorless solution tur
KIM [24]

Answer:

The molarity of HCl is 0.138 M

Explanation:

The titration reaction is as follows:

2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O

When no more HCl is left, the small excess of Ca(OH)₂ added will cause the pH to rise and the indicator will turn. At this point, the number of moles of Ca(OH)₂ added will be the same as half the number of moles of HCl since 1 mol Ca(OH)₂ reacts with 2 moles HCl. Then:

At the endpoint:

moles Ca(OH)₂  = moles HCl / 2

Knowing the number of moles of Ca(OH)₂ added, we can calculate the number of moles of the acid:

mol Ca(OH)₂ = Volume added * concentration of Ca(OH)₂

mol Ca(OH)₂ = 0.0265 l * 0.130 mol/l = 3.45 x 10⁻³ mol Ca(OH)₂

The number of moles of HCl will be:

mol HCl = 2 * 3.45 x 10⁻³ mol = 6.89 x 10⁻³ mol HCl

This number of moles was present in 50.0 ml, then, in 1000 ml:

mol of HCl in 1000 ml = 6.89 x 10⁻³ mol HCl * (1000ml / 50ml) = 0.138 mol

Then:

Molarity HCl = 0.138 M

7 0
4 years ago
Some water released 7800 J of energy when cooled from 78°C to 33°C. What was the mass of the water?
Karo-lina-s [1.5K]

Answer:

-41. 47

Explanation:

m = q / Cp x T

m = Mass

q = Energy (or joules)

Cp = Heat Capacity

T = Change in Temperature

Water's heat capacity is always 4.18.

This is the formula you'll need for change in temperature:

Final - Initial

So, 33 - 78 = -45

m = 7800 / 4.18 x -45

= -41.47

4 0
2 years ago
The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr
GREYUIT [131]

Answer:

The K_b expression for the weak base equilibrium is:

K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}

Explanation:

(CH_3)_3N(aq)+H_2O(l)\rightlefharpoons (CH_3)_3NH^++OH^-(aq)

The expression of the equilibrium constant of base K_c can be given as:

K_c=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N][H_2O]}

]K_b=K_c\times [H_2O]=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}

As we know, water is pure solvent, we can put [H_2O]=1

K_b=K_c\times 1=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}

So, the the K_b expression for the weak base equilibrium  is:

K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}

6 0
3 years ago
Why is cl2 a subcript​
vazorg [7]

Answer:

In Cl_2, the 2 is a subscript because it indicates there are 2 of the same elements. The Lewis structure would display it as Cl-Cl.

On the other hand, a superscript would indicate a specific charge.

All subscripts show the amount of the specific element there is.

An example would be O_2\\ or N_2, they both show that there are 2 of the same elements.

If the subscript is outside a parenthesis such as Ca_3(PO_4)_2 it indicates there are 2 PO_4 molecules.

5 0
3 years ago
Substrate: N-benzoyl-L-tyrosine ethyl ester (BTEE) 0.001M in 50% aqueous
andreev551 [17]

0.1 mL of the stock solution of the enzyme is taken and made up to 5.0 mL with 0.001M HCl in order to prepare a 50-fold diluted enzyme.

<h3>What is dilution?</h3>

Dilution is a process of making a solution of lower concentration from a solution of higher concentration by the addition of solvent to a given volume of the solution of higher concentration.

Dilution of solutions is done using the dilution formula in order to determine the given volume of diluent or stock solution required. The dilution formula is given below:

  • C1V1 = C2V2

where:

  • C1 = Initial concentration of enzyme
  • C2 = Final concentration of enzyme
  • V1 = Initial volume
  • V2 = Final volume

For the enzyme dilution;

C1 = 1 mg/mL

C2 = 1/50 mg/ml = 0.02 mg/ml

V= ?

V2 = 5 ml

V1 = C2V2/C1

V1 =  0.02 * 5/1 = 0.1 mL

Therefore, 0.1 mL of the stock solution of the enzyme is taken and made up to 5.0 mL with 0.001M HCl in order to prepare a 50-fold diluted enzyme.

Learn more about dilution at: brainly.com/question/24881505

#SPJ1

3 0
2 years ago
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