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love history [14]
3 years ago
13

A reaction in which A, B, and C react to form products is first order in A, second order in B, and zero order in C. a. Write a r

ate law for the reaction. b. What is the overall order of the reaction? c. By what factor does the reaction rate change if [A] is doubled (and the other reactant concentrations are held constant)? d. By what factor does the reaction rate change if [B] is doubled (and the other reactant concentrations are held constant)? e. By what factor does the reaction rate change if [C] is doubled (and the other reactant concentrations are held constant)? f. By what factor does the reaction rate change if the concentrations of all three reactants are doubled?
Chemistry
1 answer:
iragen [17]3 years ago
6 0

Answer:

a. r = k. [A]¹. [B]².[C]⁰

b. 3

c. 2

d. 4

e. 1

f. 8

Explanation:

A reaction in which A, B, and C react to form products is first order in A, second order in B, and zero order in C.

a. Write a rate law for the reaction.

r = k. [A]¹. [B]².[C]⁰

where,

r is the <em>rate of the reaction</em>

k is the <em>rate constant</em>

[X]ⁿ are the <em>molar concentrations</em> of each reactant raised to its <em>reaction order</em>

b. What is the overall order of the reaction?

The overall order of reaction is the sum of the individual orders of reaction, that is, 1 + 2 + 0 = 3.

c. By what factor does the reaction rate change if [A] is doubled (and the other reactant concentrations are held constant)?

If A is doubled, then:

r' = k. [2A]¹. [B]².[C]⁰= 2 k. [A]¹. [B]².[C]⁰ = 2 . r

The factor is 2.

d. By what factor does the reaction rate change if [B] is doubled (and the other reactant concentrations are held constant)?

If B is doubled, then:

r' = k. [A]¹. [2B]².[C]⁰ = 4. k. [A]¹. [B]².[C]⁰ = 4 . r

The factor is 4.

e. By what factor does the reaction rate change if [C] is doubled (and the other reactant concentrations are held constant)?

If C is doubled, then:

r' = k. [A]¹. [B]².[2C]⁰ = 1. k. [A]¹. [B]².[C]⁰ = 1 . r

The factor is 1.

f. By what factor does the reaction rate change if the concentrations of all three reactants are doubled?

r' = k. [2A]¹. [2B]².[2C]⁰ = 2.4.1.k. [A]¹. [B]².[C]⁰ = 8 .r

The factor is 8.

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Given the model from the question,

  • The products are: N₂, H₂O and H₂
  • The reactants are: H₂ and NO
  • The limiting reactant is H₂
  • The balanced equation is: 3H₂ + 2NO —> N₂ + 2H₂O + H₂

<h3>Balanced equation </h3>

From the model given, we obtained the ffolowing

  • Red => Oxygen
  • Blue => Nitrogen
  • White => Hydrogen

Thus, we can write the balanced equation as follow:

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

  • Reactants: H₂ and NO
  • Product: N₂, H₂O and H₂

<h3>How to determine the limiting reactant</h3>

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

3 moles of H₂ reacted with 2 moles of NO.

Therefore,

5 moles of H₂ will react with = (5 × 2) / 3 = 3.33 moles of NO

From the calculation made above, we can see that only 3.33 moles of NO out of 4 moles given are required to react completely with 5 moles of H₂.

Thus, H₂ is the limiting reactant

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brainly.com/question/14735801

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