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4 years ago

How many grams are in 11.9 moles of chromium?

Chemistry

2 answers:

Black_prince [1.1K]4 years ago

8 0

1mole ----- 52g Cr
11,9moles --- x

x = 11,9*52/1 = 618,8[g]

raketka [301]4 years ago

7 0

Explanation:

It is known that one mole of chromium or molar mass of chromium is 51.99 g/mol.

It is given that number of moles is 11.9 moles.

Therefore, calculate the mass of chromium in grams as follows.

No. of moles = $\frac{mass in grams}{Molar mass}$

mass in grams = No. of moles × Molar mass

= 11.9 moles × 51.99 g/mol

= 618.68 g

Thus, we can conclude that there are 618.68 g in 11.9 moles of chromium.

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balu736 [363]

Answer:

0.14 M

Explanation:

To determinate the concentration of a new solution, we can use the equation below:

C1xV1 = C2xV2

Where C is the concentration, and V the volume, 1 represents the initial solution, and 2 the final one. So, first, the initial concentration is 1.50 M, the initial volume is 55.0 mL and the final volume is 278 mL

1.50x55.0 = C2x278

C2 = 0.30 M

The portion of 139 mL will be the same concentration because it wasn't diluted or evaporated. The final volume will be the volume of the initial solution plus the volume of water added, V2 = 139 + 155 = 294 mL

Then,

0.30x139 = C2x294

C2 = 0.14 M

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3 years ago

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Determine the standard enthalpy of formation in kJ/mol for NO given the following information about the formation of NO2 under s

Zarrin [17]

Answer:

90.3 kJ/mol

Explanation:

Let's consider the following thermochemical equation.

2 NO(g) + O₂(g) → 2 NO₂(g) ∆H°rxn = –114.2 kJ

We can find the standard enthalpy of formation for NO using the following expression.

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × ΔH°f(O₂(g))

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × 0 kJ/mol

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g))

ΔH°f(NO(g)) = (2 mol × ΔH°f(NO₂(g)) - ∆H°rxn) / 2 mol

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3 years ago

Identify which sets of quantum numbers are valid for an electron. Note that each set is ordered (n,l,ml,ms).

Fynjy0 [20]

Answer:

The answer to your question is:

Explanation:

Quantum numbers have the numbers

n = from 1 to 7

l = s = 0 p = 1 d = 2 f= 3

m = ± l

s = ±1/2

Group of answer choice.

A) 2, -1. 1, -1/2 The option is incorrect "l" could not be negative

B) 2, 1, 0 , 1/2 The option is posible

C) 3, 2, 1, -1 This option is incorrect "s" can not value -1

D) 4, 3, 2, 1/2 This option is correct

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G) 1, 1, 0, -1/2 This option is incorrect the second number could not be 1.

H) 3, 0, 0, 1/2 This option is incorrect "l" can not value 0

I) 0, 2, 0, 1/2 This option is incorrect, n can not value 0

J) 3, 2, 2, 1/2 This option is correct

K) 1, 2, 0, -1/2 This option is incorrect "l" can not value 2.

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3 years ago

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Explanation:

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