(a) The 1H NMR spectrum of DMF exhibits three signals. Upon treatment with excess LAH followed by water, DMF is converted into a
new compound that exhibits only one signal in its 1H NMR spectrum. Explain. DMF, like most , exhibits restricted rotation about the bond between the carbonyl group and the nitrogen atom. This restricted rotation causes the groups to be in different electronic environments. They are not chemically equivalent, and will therefore produce different signals (in addition to the signal from the other proton in the compound). Upon treatment with excess LAH followed by water, DMF is to an amine that exhibit restricted rotation. As such, the methyl groups chemically equivalent and will together produce . (b) Based on your answer to part a, how many signals do you expect in the 13C NMR spectrum of DMF? Restricted rotation causes the methyl groups to be in electronic environments. As a result, the 13C NMR spectrum of DMF should have .
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Answer : The enthalpy change for the process is 52.5 kJ/mole.
Explanation :
Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution
where,
q = heat released by the reaction
= heat absorbed by the calorimeter
= heat absorbed by the solution
= specific heat of calorimeter =
= specific heat of water =
= mass of water or solution =
= change in temperature =
Now put all the given values in the above formula, we get:
Now we have to calculate the enthalpy change for the process.
where,
= enthalpy change = ?
q = heat released = 2626.61 J
n = number of moles of copper sulfate used =
Therefore, the enthalpy change for the process is 52.5 kJ/mole.