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3 years ago

5

Karen is 17 years ild and has a BMI that indicates appropriate weight.She loves to eat all kinds of food. which strategy will be

st help karen maintain her health?

1 answer:

lora16 [44]3 years ago

4 0

Answer

She needs to set boundaries

Explanation:

Diet

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Determine the oxidation number of sodium in Na202

Olegator [25]

Answer:

+1

Explanation:

Na₂O₂

NOTE: the oxidation number of oxygen is always –2 except in peroxides where it is –1.

Thus, we can obtain the oxidation number of sodium (Na) in Na₂O₂ as illustrated below:

Na₂O₂ = 0 (oxidation number of ground state compound is zero)

2Na + 2O = 0

O = –1

2Na + 2(–1) = 0

2Na – 2 = 0

Collect like terms

2Na = 0 + 2

2Na = 2

Divide both side by 2

Na = 2/2

Na = +1

Thus, the oxidation number of sodium (Na) in Na₂O₂ is +1

5 0

3 years ago

Sample of 200mls of 0.5 sulphuric acid,was asked to produce 1.2M of the new solution.Calculate the volume of the new solution

AlladinOne [14]

Answer:

$V_2=83.3mL$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the volume of the new solution by using the general formula of dilution:

$V_1M_1=V_2M_2$

In such a way, we solve for the final volume, V2, to obtain:

$V_2=\frac{200mL*0.5M}{1.2M}\\\\V_2=83.3mL$

Regards!

3 0

3 years ago

Look at the Recording station detector on the upper left side of the Gizmo. What happens when the seismic waves hit the recordin

Ne4ueva [31]

Answer:

I don’t know what recording station you’re referring to but, When seismic waves reach the seismograph, a graphical record, or seismogram, is produced

Explanation:

4 0

3 years ago

How many grams of ethane gas (C2H6) are in a 12.7 liter sample at 1.6 atmospheres and 24°C? Show all work used to solve this pro

dexar [7]

n = PV/RT

p = 1.6 atm

v = 12.7L

R = 0.0821

T = 24°C which is equivalent to 297.15 degrees k

n = (16 × 12.7) / (0.0821 × 297.15)

n = 20.32 / 24.39

n = 0.83 mol

C = 12.90

H = 1.0079

C2 = 12.010 × 2 = 24.02

H6 = 1.0079 × 6 = 6.0474

C2H6 = 30.0674

Ethane times n which is 30.0674 × 0.83mol

= 24.95 grams of C2H6. Which is Ethane.

4 0

3 years ago

A water treatment plant receives the source water with an average Ca2+ concentration of 46.9 mg/L and Mg2+ concentration of 14.8

Veronika [31]

Answer:

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

Explanation:

Concentration of calcium ions = 46.9 mg/L

Concentration of magnesium ions = 14.8 mg/L

Volume of solution treated everyday , V= 80 million gal

= $80\times 10^6 gal=4.546\times 80\time 10^6 L=3.637\times 10^8 L$

1 gallon = 4.546 Liter

Mass of calcium ion in V = $46.9 mg/L\times 3.637\times 10^8 L$

= $1.706\times 10^{10} mg$

1 mg = 0.001 g

$1.706\times 10^{7} g$

Moles of calcium ions = $\frac{1.706\times 10^{7} g}{40 g/mol}=426,500 mol$

From 1 mole of calcium ion 1mol of carbonate is formed . then from 426,500 moles of calcium ion will form :

$\frac{1}{1}\times 426,500 mol=426,500 mol$ of calcium carbonate

Mass of 426,500 moles of calcium carbonate:

426,500 mol × 100 g/mol = 42,650,000 g = 42,650 kg

Mass of magnesium ion in V = $14.8 mg/L\times 3.637\times 10^8 L$

= $5.382\times 10^{9} mg$

= $5.382\times 10^{6} g$

Moles of magnesium ions = $\frac{5.382\times 10^{6} g}{24 g/mol}=224,250 mol$

From 1 mole of magnesium ion 1 mol of magnesium hydroxide is formed . then from 224,250 moles of magnesium ion will form :

$\frac{1}{1}\times 224,250 mol=224,250 mol$ of magnesium hydroxide

Mass of 224,250 moles of magnesium hydroxide:

224,250 mol × 58 g/mol = 13,006,500 g = 13,006.5 kg

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

3 0

3 years ago