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Alexeev081 [22]
3 years ago
8

Solve the equation: 7(x + 8) = 49​

Mathematics
1 answer:
eduard3 years ago
4 0

Answer:

-1

Step-by-step explanation:

1.)Reorder the terms:

7(8 + x) = 49

(8 * 7 + x * 7) = 49

(56 + 7x) = 49

2.)Solving

56 + 7x = 49

3.)Solving for variable 'x'.

4.)Move all terms containing x to the left, all other terms to the right.

5.)Add '-56' to each side of the equation.

56 + -56 + 7x = 49 + -56

6.)Combine like terms: 56 + -56 = 0

0 + 7x = 49 + -56

7x = 49 + -56

7.)Combine like terms: 49 + -56 = -7

7x = -7

8.)Divide each side by '7'.

x = -1

9.)Simplifying

x = -1

Hope this helps

plz like and brainy

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An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
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The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

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Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
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Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

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So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
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Step-by-step explanation:

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Step-by-step explanation:

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<em>See attached for answer</em>

<em />

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