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3 years ago

How many moles of aluminum are in 1.204 x 1023 atoms of aluminum?

Chemistry

2 answers:

goblinko [34]3 years ago

6 0

C i just took the test

zepelin [54]3 years ago

5 0

Answer:

D. 5 moles

Explanation:

Just took the test :)

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The chemical and physical actions of groundwater form what?

Irina18 [472]

Chemical and physical actions of groundwater form Karst topography.

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4 years ago

What mass of limestone (in kg) would be required to completely neutralize a 15.5 billion-liter lake that is 1.7×10^−5 M in H2SO4

Alinara [238K]

The complete balanced chemical reactions are:

HNO3 => CaCO3 + 2HNO3 → Ca(NO3)2 + H2O + CO2(g)

H2SO4 => CaCO3 + H2SO4 → CaSO4 + H2O + CO2(g)

So we see that 1 mole of CaCO3 is needed for 2 moles of HNO3 and similarly to 1 mole of H2SO4.
The number of moles can be calculated as the product of volume and molarity, so:

moles H2SO4 = 1.7×10^−5 M * (15.5 x 10^9 L) = 263,500 mol H2SO4

moles HNO3 = 8.9×10^−6 M * (15.5 x 10^9 L) = 137,950 mol HNO3

So the total moles of CaCO3 required is:

moles CaCO3 = 263,500 mol * 1 + 137,950 mol * (1/2)

moles CaCO3 = 332,475 mol

The molar mass of CaCO3 is 100.086 g/mol, so the mass is:

mass CaCO3 = 332,475 mol * 100.086 g/mol

mass CaCO3 = 33,276,092.85 g = 33.3 x 10^3 kg

5 0

3 years ago

What anions generally form precipitates? What are the exceptions?

8_murik_8 [283]

Answer:

Carbonates (CO3-2), phosphates (PO4-3) and sulfides (S-2) are insoluble.

The exceptions are the alkali metals and the ammonium ion.

6 0

4 years ago

Read 2 more answers

For most substances, the distance between the particles is smallest when the substance

olchik [2.2K]

Is a solid? has strong intermolecular forces?

3 0

3 years ago

What is the molarity of a NaOH solution if 28.2 mL of a 0.355 M H2SO4 solution is required to neutralize a 25.0-mL sample of the

Anni [7]

Answer:

A) 0.801

Explanation:

The reaction that takes place is:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

First we calculate the H₂SO₄ moles that reacted:

0.355 M * 28.2 mL = 10.011 mmol H₂SO₄

Now we convert H₂SO₄ moles to NaOH moles:

10.011 mmol H₂SO₄ * $\frac{2mmolNaOH}{1mmolH_2SO_4}$ = 20.022 mmol NaOH

Finally we calculate the molarity of the NaOH solution:

20.022 mmol NaOH / 25.0 mL = 0.801 M

So the answer is option A.

3 0

3 years ago