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3 years ago

Help me out? thank you.

Chemistry

2 answers:

Assoli18 [71]3 years ago

7 0

I’m not sure of how to do the math part.. but you’ll have to solve for PE first, and then for KE. finding the velocity for the KE formula while doing so.

Vladimir [108]3 years ago

3 0

Wow very difficult I am so confused

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Help plz 50 points <3

Rufina [12.5K]

Answer:

I believe the answer is the last one answer D: Neutral elements

Explanation:

Ionic bonds are formed through the exchange of valence electrons between atoms, typically a metal and a nonmetal. ... Ionic compounds are typically neutral. Ionic compounds generally form between elements that are metals and elements that are nonmetals.

Hope this helps please mark brainliest :)

8 0

2 years ago

If 200.0 grams of aluminum chloride react with calcium, how many moles of Al are produced?

irina [24]

1.49 moles of Al will be produced. Hope this helps you.

8 0

3 years ago

Three kilograms of steam is contained in a horizontal, frictionless piston and the cylinder is heated at a constant pressure of

lakkis [162]

Answer:

Final temperature: 659.8ºC

Expansion work: 3*75=225 kJ

Internal energy change: 275 kJ

Explanation:

First, considering both initial and final states, write the energy balance:

$U_{2}-U_{1}=Q-W$

Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:

$dw=Pdv$

The pressure is constant, so: $w=P(v_{2}-v_{1} )=0.5*100*1.5=75\frac{kJ}{kg}$ (There is a multiplication by 100 due to the conversion of bar to kPa)

So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):

$U_{2}-U_{1}=500-(3*75)=275kJ$

On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:

$P_{1}V_{1}=nRT_{1}$

$P_{2}V_{2}=nRT_{2}\\V_{2}=2.5V_{1}\\P_{2}=P_{1}\\2.5P_{1}V_{1}=nRT_{2}$

Subtracting the first from the second:

$1.5P_{1}V_{1}=nR(T_{2}-T_{1})$

Isolating $T_{2}$ :

$T_{2}=T_{1}+\frac{1.5P_{1}V_{1}}{nR}$

Assuming that it is water steam, n=0.1666 kmol

$V_{1}=\frac{nRT_{1}}{P_{1}}=\frac{8.314*0.1666*373.15}{500} =1.034m^{3}$

$T_{2}=100+\frac{1.5*500*1.034}{0.1666*8.314}=659.76$ ºC

7 0

3 years ago

using the equation, c5h12 8o2 arrow 5co2 6h2o, if 108 g of water are produced, how many grams of oxygen were consumed?

vfiekz [6]

Molar mass:

H₂O = 18.0 g/mol

O₂ = 32.0 g/mol

C₅H₁₂ + 8 O₂ -> 5 CO₂ + 6 H₂O

8 x (32 g ) ------------ 6 x (18 g )
mass O₂ ------------ 108 g H₂O

mass O₂ = 108 x 8 x 32 / 6 x 18

mass O₂ = 27648 / 108

mass O₂ = 256 g

hope this helps!

8 0

3 years ago

Find the actual yield when the theatrical yield is 1.09g and percent yield is 90%.

ioda

Actual yield/Theoretical yield *100= Percentage yield. So Actual yield = Percentage yield*Theoretical yield.
Therefore actual yield= 90/100 * 1.09g = 0.98g

Actual yield: 0.98 g

3 0

2 years ago