Answer:
C
Explanation:
According to John Dalton's Atomic theory, it was about the structure of the atoms: "Each chemical element is composed of extremely small particles that are indivisible and cannot be seen by the naked eye, called atoms"
Answer:
The answer to your question is 15500 mg of MgSO₄ 7H₂O
Explanation:
Data
Volume = 30 ml
Concentration = 0.3 M
Formula MgSO4∗7H2O
Process
1.- Calculate the number of moles needed
Molarity = moles / volume
Solve for moles
moles = Molarity x volume
Substitution
moles = 0.3 x 0.03 l
moles = 0.009 moles of MgSO₄
2.- Calculate the molecular mass of MgSO4∗7H2O
molecular mass = 24 + 32 + 64 + 14 + 112
= 246 g
3.- Get the proportion MgSO4 :7H2O, this proportion is 1 : 7
4.- Calculate the amount of MgSO4∗7H2O
Simplification
15.5 g = 15500 mg
To solve this problem, we use the formula:
C1 V1 = C2 V2
where C is concentration and V is volume
15% * 1000 mL = 65% * V2
V2 = 230.77 mL
<span>So about 230.77 mL of 65% stock solution should be diluted
with water to 1000 mL to make 15% solution.</span>
Answer:
(1). The vapor pressure is 91 mmHg at 20°C.
(2). No, benzene will not boil at sea level.
Explanation:
Benzene, C6H6 is an aromatic, liquid compound with with molar mass of 78.11 g/mol and Melting point of 5.5 °C. One of the importance or the uses of benzene is in the making of fibres and plastics.
The vapour pressure of benzene can be gotten from the table showing the vapor pressure of different liquids.
Boiling point can simply be defined as the point or the temperature in which the vapor pressure is the same with the atmospheric pressure.
The atmospheric pressure is 760mmHg, while the vapor pressure at sea level is at the temperature of 15°C which is equal to 71 mmHg( from the table showing the vapor pressure of different liquids).
71 mmHg is not equal to 760 mmHg, thus, at sea level Benzene will not boil.