Someone pls help me With this I will make you as brain

In a reaction of a potential new fuel, it is found that when 2.81 moles of the fuel combusts, 1,612 kJ of energy is released. Wh

Tema [17]

Answer:

-573.67

Explanation:

whenever energy is released in a chemical reaction, we would then expect the delta H of the reaction to be negative because the reaction is an exothermic reaction.

now we have that 2.81 moles of fuel when it combusts would releases 1612kJ of energy

thus, 1 mole will release 1612/2.81 = -573.67kJ of heat

Therefore the delta H of the reaction = -573.67 kJ/mol

3 0

3 years ago

An atom of Fe has 30 neutrons. What is the mass number of this atom?

SVETLANKA909090 [29]

Answer:

56

Explanation:

The mass number of an atom is a sum of its number of protons and neutrons. Iron (Fe) has an atomic number of 26. This means that it has 26 protons. Since we know it has 26 protons and are told it has 30 neutrons. The mass number of this atom of Iron is 26+30 = 56

Hope this helped!

7 0

3 years ago

Can someone help me? It needs to have a diagram that has arrows.

daser333 [38]

Answer: The enthalpy change for formation of butane is -125 kJ/mol

Explanation:

The balanced chemical reaction is,

$C_4H_{10}(g)+\frac{13}{2}O_2(g)\rightarrow 4CO_2(g)+5H_2O(l)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f{products}]-[n\times H_f{reactants}]$

Putting the values we get :

$\Delta H=[4\times H_f_{CO_2}+5\times H_f_{H_2O}]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times H_f_{O_2}]$

$-2877=[(4\times -393)+(5\times -286)]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times 0]$

$H_f_{C_4H_{10}=-125kJ/mol$

Thus enthalpy change for formation of butane is -125 kJ/mol

5 0

3 years ago

A pool is 59.8 m long and 26.6 m wide. If the average depth of water is 3.70 ft, what is the mass (in kg) of water in the pool?

klio [65]

Given :

Length , l = 59.8 m.

Breadth , b = 26.6 m.

Depth , d = 3.7 ft .

Density of water , $\rho=1\ g/ml=1000\ kg/m^3$ .

To Find :

Mass of water in pool .

Solution :

First we will covert depth into m from ft .

$1\ ft =0.3\ m$

For ,

$3.7\ ft=0.3\times 3.7\ m\\3.7\ ft=1.11\ m$

So , volume of pool is :

$V=59.8\times 26.6\times 1.11\ m^3\\\\V=1765.65\ m^3$

We know , density is given by :

$\rho=\dfrac{m}{V}$

So , $m=\rho V$

Putting given values in above equation :

$m=1000\times 1765.65\ kg\\\\m=1.77\times 10^6\ kg$

Hence , this is the required solution.

7 0

3 years ago

What is the high court in South Africa called?

blsea [12.9K]

Answer:

The Supreme Court of Appeal

Explanation:

The Supreme Court of Appeal is based in Bloemfontein in the Free State. Except for the Constitutional Court, it is the highest court in South Africa and it only deals with cases sent to it from the High Court.

5 0

3 years ago