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asambeis [7]
4 years ago
7

Classify each process as an endothermic or exothermic process. drag the appropriate items to their respective bins. helpreset ex

othermic breaking solvent-solvent attractionsbreaking solute-solute attractions endothermic forming solute-solvent attractions
Chemistry
2 answers:
myrzilka [38]4 years ago
7 0
Answers:

1) <span>Breaking Solvent-Solvent Attractions is an Endothermic Process.

2) </span><span>Breaking Solute-Solute Attractions is an Endothermic Process.

3) </span><span>Forming Solute-Solvent Attractions is an Exothermic Process.

Explanation:
                   When a solute is dissolved in solvent it either releases heat or absorbs heat depending upon the the interactions broken and interactions formed. At first, the solvent solvent interactions are broken , this process requires heat which is provided either from external source or is provided by the forming of solute solvent bond forming process which is exothermic.

When the solvent molecules get apart the solute particles enter to form interactions with elimination of heat. So, if the heat required to break solvent solvent interactions is greater than the heat provided by solute solvent interactions formation then the solute will not dissolve at room temperature and vice versa.</span>
lora16 [44]4 years ago
5 0

Breaking solvent-solvent attractions and breaking solute-solute attractions : <u>endothermic process</u>

Forming solute-solvent attractions : <u>exothermic process</u>

<h3>Further explanation </h3>

In mixing the two solutions, it will require energy to break the attraction of each solution and create a new attraction that produces energy.

If both are equal then there will be no heat released or received so that the delta H solution is 0, which indicates that the solution is ideal

The ideal solution occurs if the attractive force between the molecules is the same as the attractive force of each solute and solvent

There are 2 kinds of deviations from Raoult's Law,

  • 1. Positive deviation

Occurs if the attractive strength between each mixture forming agent is stronger than the attractive in the mixture

(X-X, Y-Y> X-Y)

This deviation produces a positive enthalpy of solution (ΔH +) which is endothermic

  • 2. Negative deviation

Occurs if the attractive force in the mixture is stronger than the attractive force of each substance

(X-Y> X-X, Y-Y)

This deviation produces an enthalpy of a negative value solution (ΔH -) which is exothermic

So that breaking solvent attractions and breaking attraction solutes require energy so it is called an endothermic process

While forming solute-attraction attractions will release heat so-called exothermic process

<h3>Learn more </h3>

Raoult's law

brainly.com/question/10165688

Deviation from Raoult's Law

brainly.com/question/13004684

When heat is added to a substance  

brainly.com/question/3417580  

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Cloud [144]

Answer: -345.2 KJ

Explanation: As we know that ,dG=dH-TdS

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3 years ago
Chloroform is an excellent solvent for extracting caffeine from water. The distribution coefficient, KD, (Cchloroform/Cwater) fo
Art [367]

The relative volumes of chloroform and water that should be used is 9:10

Concentration of solution in chloroform = 90 ( moles of chloroform )

Concentration of solution in water = 10 ( moles of water )

Dissociation constant at 25^oC; K_D = 10

K_D = Concentration of solution in chloroform / Concentration of solution in water

Meaning;

K_D = \frac{\frac{mole\ of\ chloroform}{volume\ of\ chloroform} }{\frac{mole\ of\ water}{volume\ of\ water} }

Since 90 mole is present in chloroform and 10 mole is present in water, Total mole of Caffeine present is 100

Now, we substitute our given values into the equation

10 = \frac{\frac{90}{volume\ of\ chloroform} }{\frac{10}{volume\ of\ water} }\\\\10 *\frac{10}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}  \\\\\frac{100}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}\\\\\frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{90}{100}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{9}{10}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = 9:10

Therefore, the relative volumes of chloroform and water that should be used is 9:10

Learn more; brainly.com/question/11060225

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