Answer:
The collision occurs at a height of 1/3 of the total height of cliff.
Explanation:
The situation is represented in the attached figure:
For the stone dropped from top of cliff we have
Initial velocity of drop= 0 m/s.
Now the time at which it attains a velocity of 2v is obtained from first equation of kinematics as

Thus the distance it covers in this time can be calculated using third equation of kinematics as

For the stone thrown upwards the velocity at collision is give as 'v' thus the velocity at which it is thrown upwards can be calculated by first equation of kinematics as

The height over which it changes it's velocity from '3v' to 'v' can be again obtained from third equation of kinematics as


Thus the collision occurs at at a fraction of 1/3 of height.
Answer: option B is correct.
Explanation:
Okay let us fill in the gap in the question;
"In a resting state, sodium (Na+) "is at a higher concentration outside the cell and potassium (K+) is more concentrated inside the cell. During an action potential, the sodium levels INCREASE inside the cell''.
The answer is option B. The levels of sodium inside the cell increase because Sodium (Na^+) enters while the potassium (K^+) moves out of the cell and NOT that the sodium(Na^+) leaves/moves out of the cell. The Sodium(Na^+) outside the content of the cell is more positive than the the content of the cell, this will enhance the sodium ion(Na^+) to move inside the cell thereby INCREASING the sodium levels in the cell.
What assignment is this and subject
Answer:
it needed to be approved by the ratification process
Answer:
camel wide variety of feet that help to move in sand without sinking into it . camel have a hump that store water a camel can go As without water and Ladt for several months