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2 years ago

A block lies on a horizontal frictionless surface and

Physics

1 answer:

zhenek [66]2 years ago

6 0

Answer:

0.1 m

Explanation:

F = Force exerted on spring = 3 N

k = Spring constant = 60 N/m

x = Displacement of the block

As the energy of the system is conserved we have

$Fx=\dfrac{1}{2}kx^2$

$\\\Rightarrow x=\dfrac{2F}{k}$

$\\\Rightarrow x=\dfrac{2\times 3}{60}$

$\\\Rightarrow x=0.1\ m$

The position of the block is 0.1 from the initial position.

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Solving both integrals, we get:

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$r_{cm}=[12.73,12.73]cm$

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