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2 years ago

Rusting of iron can be prevented by wrapping iron articles in newspaper true or false

Chemistry

1 answer:

pantera1 [17]2 years ago

3 0

false, the rusting of iron can be prevented by painting, oiling, greasing or varnishing its surface.

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In the sodium-potassium pump, sodium ion release causes two K ions to be released into the cell. __________________ True False

Solnce55 [7]

Answer:

false

Explanation:

As we know that in sodium-potassium pump .

sodium potassium move 3Na+ outside the cells

and moving 2k+ inside the cells

so that we can say that given statement is false

Answer FALSE

6 0

2 years ago

The temperature of 6.24 L of a gas is increased from 25.0°C to 55.0°C at constant pressure. The new volume of the gas is Questio

Sphinxa [80]

Answer:

Heating this gas to 55 °C will raise its volume to 6.87 liters.

Assumption: this gas is ideal.

Explanation:

By Charles's Law, under constant pressure the volume $V$ of an ideal gas is proportional to its absolute temperature $T$ (the one in degrees Kelvins.)

Alternatively, consider the ideal gas law:

$\displaystyle V = \frac{n \cdot R}{P}\cdot T$ .

$n$ is the number of moles of particles in this gas. $n$ should be constant as long as the container does not leak.
$R$ is the ideal gas constant.
$P$ is the pressure on the gas. The question states that the pressure on this gas is constant.

Therefore the volume of the gas is proportional to its absolute temperature.

Either way,

$V\propto T$ .

$\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1}$ .

For the gas in this question:

Initial volume: $V_1 = \rm 6.24\; L$ .

Convert the two temperatures to degrees Kelvins:

Initial temperature: $T_1 = \rm 25.0\;\textdegree{C} = (25.0 + {\rm 273.15})\; K = 298.15\;K$ .
Final temperature: $T_1 = \rm 55.0\;\textdegree{C} = (55.0 + {\rm 273.15})\; K = 328.15\;K$ .

Apply Charles's Law:

$\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1} = \rm 6.24\;L \times \frac{328.15\; K}{298.15\;K} = 6.87\;L$ .

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3 years ago

What is the molarity to the nearest hundredth of a solution made by dissolving 1.71 moles of NaOH in enough water to produce an

Natali [406]

Answer:

Explanation:

50 is the volume

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2 years ago

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How much heat is required to increase the temperature of 100.0 grams of iron from 15.0oC to 40.2oC? (The specific heat of iron i

Ksenya-84 [330]

Answer is: 1160 J of heat Is required to increase the temperature.
m(Fe) = 100 g.
∆T = 40,2 - 15 = 25,2°C.
C(Fe) = 0,46 J/g•°C.
Q = m(Fe) • C • ∆T.
Q = 100 g • 0,46 J/g•°C • 25,2°C
Q = 1160 J.
C - specific heat.

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2 years ago

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Nuclear Processes Unit Test

Finger [1]

Answer:

Explanation:

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3 years ago

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Rusting of iron can be prevented by wrapping iron articles in newspaper true or false​

Rusting of iron can be prevented by wrapping iron articles in newspaper true or false