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blagie [28]
3 years ago
5

Rusting of iron can be prevented by wrapping iron articles in newspaper true or false​

Chemistry
1 answer:
pantera1 [17]3 years ago
3 0

false, the rusting of iron can be prevented by painting, oiling, greasing or varnishing its surface.

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A dry soil sample has a volume of 500 mL. After 400 mL of water are added to the soil, the soil becomes saturated with 150 mL of
Lerok [7]
The Answer is 50. hope this helps
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Name given to a negatively charged atom?
monitta
An anion is a negatively charged particle.
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3 0
3 years ago
What is the density of Iodine gas at 2.36 atm and 65.0 C?
timurjin [86]

The density : 21.63 g/L

<h3>Further explanation</h3>

The gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

T = 65+273=338 K

P=2.36 atm

MW Iodine gas (I₂)=254

The density :

\tt \rho=\dfrac{P\times MW}{RT}\\\\\rho=\dfrac{2.36\times 254}{0.082\times 338}=21.63~g/L

4 0
3 years ago
A compound that is usually used as a fertilizer can also be used as a powerful explosive. the compound has the composition 35.00
maxonik [38]

Answer:

             Empirical Formula  =  NH₄NO₃ (Ammonium Nitrate)

Solution:

Step 1: Calculate Moles of each Element;

                      Moles of N  =  %N ÷ At.Mass of N

                      Moles of N  = 35.0 ÷ 14

                      Moles of N  =  2.5 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  = 59.96 ÷ 16

                      Moles of O  =  3.7475 mol


                      Moles of H  =  [100% - (%N + %O)] ÷ At.Mass of H

                      Moles of H  = [100% - (35.0 + 59.96)] ÷ 1.008

                      Moles of H  = [100% - 94.96] ÷ 1.008

                      Moles of H  = 5.04 ÷ 1.008

                      Moles of H  =  5 mol

Step 2: Find out mole ratio and simplify it;

                N                                        H                                     O

               2.5                                       5                                3.7475

            2.5/2.5                                5/2.5                          3.7475/2.5

                 1                                         2                                     1.5

Multiply Mole Ratio by 2,

                 2                                         4                                     3

Result:

         Empirical Formula  =  N₂H₄O₃

Or,

         Empirical Formula  =  NH₄NO₃

This empirical formula is also a Molecular Formula for Ammonium Nitrate a well known Fertilizer and often misused in the formation of Explosives.

4 0
3 years ago
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