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Dimas [21]
3 years ago
6

The evaporation of liquid water from the surface of Earth is an important step in the water cycle. How do water molecules obtain

enough kinetic energy to escape into the gas state?
45POINTS
Chemistry
2 answers:
Alex777 [14]3 years ago
6 0
<span>Well, during the day, the water, as well as the surfaces surrounding the water, are heated by various thermodynamic processes: conduction, convection, radiation, etc. This in turn warms the water molecules in the lakes, streams, rivers, and oceans, thereby transferring heat (their kinetic energy) to the water molecules, which in turn receive that energy from the surrounding surfaces, or directly via radiation/insolation from the sun. When the water molecules attain enough energy, some of them attain enough energy to escape the surface of the liquid and enter the gas phase. Hence, as water is heated, more and more water molecules attain enough kinetic energy to enter the gas phase.</span>
Nata [24]3 years ago
3 0
The water molecules obtain enough kinetic energy by getting heat from the sun to make it into a gas state.
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opinion b

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the product of neutralization reaction between hcl and CA(oh)2 is option b.

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How many times more massive is an oxygen atom than a hydrogen atom?
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An oxygen atom is 16x more massive than a hydrogen atom.

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How many molecules are there in 5.0g of C2H5OH?
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About 6.5x10^22 molecules. (5g C2H5OH)x(1 mol C2H5OH/46g C2H5OH)x(6.02x10^23 molecules C2H5OH/1 mol C2H5OH)=(3.01E24)/46=6.5x10^22. Let me know if this helped!
4 0
3 years ago
10 points!! Please give me work with it and I will mark as brainlist.
Georgia [21]

Answer: The molecular formula will be C_2H_4O_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 40.0 g

Mass of O = 53.3 g

Mass of H = 6.66 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40.0g}{12g/mole}=3.33moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.66g}{1g/mole}=6.66moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{3.33}{3.33}=1

For O =\frac{3.33}{3.33}=1

For H = \frac{6.66}{3.33}=2

The ratio of C : O : H = 1: 1: 2

Hence the empirical formula is COH_2

The empirical weight of COH_2 = 1(12)+1(16)+2(1)= 30g.

The molecular weight = 60 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{60}{30}=2

The molecular formula will be=2\times CH_2O=C_2H_4O_2

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