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jeka57 [31]
4 years ago
10

How do u find a worm hole

Physics
2 answers:
OlgaM077 [116]4 years ago
7 0

go outside for like 2 seconds lol........ in russia, wormhole finds you

Zinaida [17]4 years ago
3 0
No one knows if they even exist so you can't really find one
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A ball is tossed with enough speed straight up so that it is in the air several seconds. (a) What is the velocity of the ball wh
xenn [34]

Answer:

The velocity of the ball at it's highest point is zero.

Explanation:

When we toss a ball upwards as we know that it's motion is an uniformly accelerated motion with acceleration = 9.81m/s^{2} in the downward direction.

Hence as we throw the ball upwards it's speed will go on decreasing as it gains height. The ball will stop gaining height when it's velocity becomes zero and the ball starts to descend again towards earth.

If the ball is tossed at an angle with the horizontal in that case it's velocity at the top most point will not be zero but in our case since the ball is tossed vertically it's velocity at the topmost point will become zero.

3 0
3 years ago
A professor sits on a rotating stool that is spinning at 10.0 rpm while she holds a heavy weight in each of her hands. Her outst
MAVERICK [17]

Answer:

0.5864 m

Explanation:

r_1 = 0.705 m

\omega_1 = 10 rpm

\omega_2 = 20.5 rpm

\left(m r_{1}^{2}\right) \omega_{1} &=\left(m r_{2}^{2}\right) \omega_{2}

r_{2}^{2} &=\frac{\left(m r_{1}^{2}\right) \omega_{1}}{\left(\omega_{2}\right)}

=\frac{\left(r_{1}^{2}\right) \omega_{1}}{\left(\omega_{2}\right)}

=\frac{\left((0.705 \mathrm{m})^{2}\right)(10 \mathrm{rpm})}{(20.5 \mathrm{rpm})}

=\sqrt{\frac{\left((0.705 \mathrm{m})^{2}\right)(10 \mathrm{rpm})}{(20.5 \mathrm{rpm})}}

r_{2} =0.5864\ m

The weights are 0.5864 m apart.

7 0
4 years ago
At what angle should the axes of two polaroids be placed so as to reduce the intensity of the incident unpolarized light to 13.
prohojiy [21]

Answer:

θ = 66.90°

Explanation:

we know that

I= \frac{I_0}{2}cos^2\theta

I= intensity of polarized light =1

I_o= intensity of unpolarized light = 13

putting vales we get

1= \frac{13}{2}cos^2\theta

⇒\theta=cos^{-1} \sqrt{\frac{1}{6.5} }

therefore θ = 66.90°

5 0
3 years ago
Just a test for my internet :)
Talja [164]

Answer:

Okay

Explanation:

3 0
2 years ago
You ride your bike from home to school, covering a distance of 3 km in 15 min. what is your average speed in km/h?
MrRa [10]
15 minutes = .25 hrs
3km/.25 hrs
3 0
3 years ago
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