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2 years ago

Name the 2 defining characteristics of a mathematical circle ?

Mathematics

1 answer:

kifflom [539]2 years ago

3 0

Answer:

the diameters of circle is the longest chord of a circle. equal chord of a circle have the equal circumference. the radius drawn perpendicular to the cord bisect the chord...the distance from the center of the circle to the longest chord ( diameter) is zero

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10 divided by 1 7/8 = 4x what is x? hurry!!

Ostrovityanka [42]

X= 20/17 ; multiply by reciprocal 10 times 8/17 =4x then 80/17=4x , divide both sides by 4 leaves you x=20/17

3 0

2 years ago

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Find the value of each variable. Line l is a tangent.

ss7ja [257]

Answer:

sorry I don't know

Step-by-step explanation:

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3 0

1 year ago

Evaluate the expression 2x-y for x=17 and y=12

mafiozo [28]

Answer:

The answer is 22.

Step-by-step explanation:

1) Replace the x with 17, and the y with 12.

2) 2(17) - 12

3) 2x17 = 34

4) 34 - 12 = 22

6 0

2 years ago

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5.) - 7(-2x - 9) = 133<br> how do you solve this

Ray Of Light [21]

Answer: x= 5

Step-by-step explanation: Distribute the -7 into the parentheses, we get 14x+63=133. You then minus 63 on the left side of the equation and on the right side of the equation. You will get 14x=70. You then solve x by dividing 70 by 14 you will get x=5.

4 0

2 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

2 years ago