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maks197457 [2]
3 years ago
14

A 53 kg person is being dragged in their sleeping bag to the lake by a 401 N force at an angle of 30°

Physics
1 answer:
masha68 [24]3 years ago
5 0

In the horizontal direction, the forces acting on the person are

• friction with magnitude <em>f</em>, opposing motion, and

• the horizontal component of the pulling force (itself with mag. <em>p</em> ) with mag. <em>p</em> cos(30º), in the direction of motion.

There is no friction in the vertical direction, so we omit any discussion of the vertical forces.

By Newton's second law, we then have

<em>p</em> cos(30º) - <em>f</em> = <em>m</em> <em>a</em> cos(30º)

where <em>m</em> is the person's mass, and <em>a</em> is their acceleration so that <em>a</em> cos(30º) is the magnitude of the horizontal component of acceleration. The person is pulled by a force of <em>p</em> = 401 N, so solve for <em>f</em> :

(401 N) cos(30º) - <em>f</em> = (53 kg) (0.59 m/s²) cos(30º)

<em>f</em> ≈ 320 N

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