Answer:
Explanation:
Voltage, V = 1.58 V
Power, P = 1 W
1 A.h
Charge, Q = 1 A.h = 1 x 3600 A.s = 3600 C
Power x time = Voltage x charge
1 x t = 1.58 x 3600
t = 1.58 x 3600 second
t = 1.58 hours
Answer:
-1486 KJ
Explanation:
The work done by an electric field on a charged body is:
W = ΔV * q
where ΔV = change in voltage
q = total charge
The total charge of Avogadro's number of electrons is:
6.0221409 * 10^(23) * -1.6023 * 10^(-19) = -9.65 * 10^(4)
The change in voltage, ΔV, is:
9.20 - (6.90) = 15.4
Therefore, the work done is:
W = -9.65 * 10^(4) * 15.4 = -1.486 * 10^6 J = -1486 KJ
The negative sign means that the motion of the electrons is opposite the electrostatic force.
1. The speed in kilometers per hour (Km/h) is 133.2 Km/h
2. Yes, the speed is exceeding the 125 Km/h limit
<h3>How to convert 37 m/s to Km/h</h3>
From the question given above, the following data were obtained:
- Speed (in m/s) = 37 m/s
- Speed (in Km/h) =?
We can convert 37 m/s to kilometers per hour (Km/h) by doing the following:
1 m/s = 3.6 Km/h
Therefore,
37 m/s = 37 × 3.6
37 m/s = 133.2 Km/h
Thus, 37 m/s is equivalent to 133.2 Km/h
<h3>2. How to determine if the speed is exceeding the limit</h3>
- Speed of car = 133.2 Km/h
- Speed limit = 125 Km/h
From the above, we can see that the speed of the car is greater than the speed limit.
Thus, we can conclude that the speed of the car is exceeding the speed limit.
Learn more about conversion:
brainly.com/question/10893215
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Charge dQ on a shell thickness dr is given by
dQ = (charge density) × (surface area) × dr
dQ = ρ(r)4πr²dr
∫ dQ = ∫ (a/r)4πr²dr
∫ dQ = 4πa ∫ rdr
Q(r) = 2πar² - 2πa0²
Q = 2πar² (= total charge bound by a spherical surface of radius r)
Gauss's Law states:
(Flux out of surface) = (charge bound by surface)/ε۪
(Surface area of sphere) × E = Q/ε۪
4πr²E = 2πar²/ε۪
<span>E = a/2ε۪
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You can find
1) time to hit the ground
2) initial velocity
3) speed when it hits the ground
Equations
Vx = Vxo
x = Vx * t
Vy = Vyo + gt
Vyo = 0
Vy = gt
y = yo - Vyo - gt^2 / 2
=> yo - y = gt^2 / 2
1) time to hit the ground
=> 8.0 = g t^2 / 2 => t^2 = 8.0m * 2 / 9.81 m/s^2 = 1.631 s^2
=> t = √1.631 s^2 = 1.28 s
2) initial velocity
Vxo = x / t = 6.5m / 1.28s = 5.08 m/s
3) speed when it hits the ground
Vy = g*t = 9.81 m/s * 1.28s = 12.56 m/s
V^2 = Vy^2 + Vx^2 = (12.56 m/s)^2 + (5.08 m/s)^2 = 183.56 m^2 / s^2
=> V = √ (183.56 m^2 / s^2) = 13.55 m/s
